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BaLLatris [955]
3 years ago
10

A car has uniformly accelerated from rest to a speed of 25m/s after traveling 75m. What is its acceleration in m/s^2

Physics
1 answer:
Roman55 [17]3 years ago
4 0
<h2><em>So there is two truths given. After an amount of time Ttotal (lets call it ‘t’): </em></h2><h2><em> </em></h2><h2><em>The car’s speed is 25m/s </em></h2><h2><em>The distance travelled is 75m </em></h2><h2><em>Then we have the formulas for speed and distance: </em></h2><h2><em> </em></h2><h2><em>v = a x t -> 25 = a x t </em></h2><h2><em>s = 0.5 x a x t^2 -> 75 = 0.5 x a x t^2 </em></h2><h2><em>Now, we know that both acceleration and time equal for both truths. So we can say: </em></h2><h2><em> </em></h2><h2><em>t = 25 / a </em></h2><h2><em>t^2 = 75 / (0.5 x a) = 150 / a </em></h2><h2><em>Since we don’t want to use square root at 2) we go squared for 1): </em></h2><h2><em> </em></h2><h2><em>t^2 = (25 / a) ^2 = 625 / a^2 </em></h2><h2><em>t^2 = 150 / a </em></h2><h2><em>Since t has the same value for both truths we can say: </em></h2><h2><em> </em></h2><h2><em>625 / a^2 = 150 / a </em></h2><h2><em> </em></h2><h2><em>Thus multiply both sides with a^2: </em></h2><h2><em> </em></h2><h2><em>625 = 150 x a, so a = 625 / 150 = 4.17 </em></h2><h2><em> </em></h2><h2><em>We can now calculate t as well t = 25 * 150 / 625 = 6</em></h2>
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A runner is jogging in a straight line at a steady Vr= 3.4km/hr. When the runner is L=8km from the finish line, a bird begins fl
Lynna [10]

Answer:

The cumulative distance that the bird travel is 13.33 Km

Explanation:

Given that,

Velocity of runner = 3.4 km/hr

Distance = 8 km

Velocity of bird = 17 km/hr

Let x is the distance from the origin where the runner run into the bird

We need to calculate the value of x

Using time of runner and bird

t_{r}=t_{b}

\dfrac{d_{r}}{v_{r}}=\dfrac{d_{b}}{v_{b}}

Put the value into the formula

\dfrac{x}{3.4}=\dfrac{8+(8-x)}{17}

17x=3.4\times8+3.4(8-x)

17x=27.2+27.2-3.4x

17x+3.4x=54.4

x=\dfrac{54.4}{20.4}

x=2.67

We need to calculate the cumulative distance that the bird travel

Using distance of bird

d_{b}=16-x

Put the value into the formula

d_{b}=16-2.67

d_{b}=13.33\ km

Hence, The cumulative distance that the bird travel is 13.33 Km

7 0
3 years ago
Anyone knows the answer to this?
nata0808 [166]

Answer:

B 7.5mph/s

Explanation:

use change in y/ change in x

8 0
3 years ago
An object slides on a level surface in the +x direction. It slows and comes to a stop with a constant acceleration of -2.45 m/s2
Stolb23 [73]

Answer:

uk = 0.25

Explanation:

Given:-

- An object comes to stop with acceleration, a = -2.45 m/s^2

Find:-

What is the coefficient of kinetic friction between the object and the floor?

Solution:-

- Assuming the object has mass (m) that slides over a rough surface with coefficient of kinetic friction (uk). There is only Frictional force (Ff) acting in the horizontal axis on the object opposing the motion (-x direction).

- We will apply equilibrium equation on the object in vertical direction.

                               N - m*g = 0

                               N = m*g

Where,  N : Contact force exerted by the surface on the floor

             g : Gravitational acceleration constant = 9.81 m/s^2

- Now apply Newton's second law of motion in the horizontal ( x-direction ):

                             - Ff = m*a

- The frictional force is related to contact force (N) by the following expression:

                              Ff = uk*N

- Substitute the 1st and 3rd expressions in the 2nd equation:

                             uk*m*g = -m*a

                             uk = a / g

- Plug in the values and solve for uk:

                             uk = - (-2.45) / 9.81

                             uk = 0.25        

8 0
3 years ago
What kind of image is formed when an object is placed at the focal point of a convex lens? Explain WHY this is the image that oc
mariarad [96]

Answer:

Since light does not actually pass through this point, the image is referred to as a virtual image. Observe that when the object in located in front of the focal point of the converging lens, its image is an upright and enlarged image that is located on the object's side of the lens.

Explanation:

4 0
3 years ago
A 65 kg cart travels at a constant speed of 4.6 m/s. What is its kinetic energy?
Talja [164]

Answer:

Explanation:

mass (m) = 65 kg

velocity (v) = 4.6 m/s

Kinetic energy (KE)

= 1/2 * m * v²

= 1/2 * 65 * 4.6²

=  687.7 J

hope it helps :)

7 0
3 years ago
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