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Elis [28]
3 years ago
8

The father of scientific management is- (

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0
I think it is d but not sure

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PHYSICS
quester [9]

Answer:

c) 8.3 x 10^24 molecules

Explanation:

First of all, we convert the volume of the glass of water from mL to cm^3:

V=250 mL = 250 cm^3

The relationship between mass and volume is:

d=\frac{M}{V}

where

d=1.00 g/cm^3 is the density of water

M is the total mass of the glass of water

V=250 cm^3 is the volume of the water in the glass

Solving for M,

M=dV=(1.00)(250)=250 g = 0.250 kg

Now we know that the mass of a single molecule of water is

m=3.0\cdot 10^{-26}kg

The total mass of the water in the glass can be written as

M=Nm

where

N is the number of molecules in the glass of water

Solving for N, we find:

N=\frac{M}{m}=\frac{0.250}{3.0\cdot 10^{-26}}=8.3\cdot 10^{24}

7 0
3 years ago
Using the free-body diagram, calculate the net force
yuradex [85]

Answer:yes it is

Explanation:

5 0
3 years ago
Read 2 more answers
Objects that transmit some light and reflect/absorb the rest of the light, like stained glass, are
11111nata11111 [884]
You are correct it is translucent because opaque let’s no light through but transparent lets almost all light through
3 0
3 years ago
a solid metal sphere of radius 3.00m carries a total charge of -5.50. what is the magnitude of the electric field at a distance
aivan3 [116]

Answer:

(a) Electric field at 0.250 m is zero.

(b)  Electric field at 2.90 m is zero.

(c) Electric field at 3.10 m is - 5.15 x 10³ V/m.

(d) Electric field at 8.00 m is - 0.77 x 10³ V/m.

Explanation:

Let Q and R are the charge and radius of the solid metal sphere. The solid metal sphere behave as conductor, so total charge Q is on the surface of the sphere.

Electric field inside and outside the metal sphere is :

E = 0 for r ≤ R ( inside )

  = \frac{KQ}{r^{2} } for r > R ( outside )

Here K is electric constant and r is the distance from the center of the metal sphere.

(a) Electric field at 0.250 m is zero as r < R i.e. 0.250 m < 3 m from the above equation.

(b)  Electric field at 2.90 m is zero as r < R i.e. 2.90 m < 3 m from the above equation.

(c) Electric field at 3.10 m is given by the relation as r > R :

E = \frac{KQ}{r^{2} }

Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 3.10 m for r in the above equation.

E = - \frac{9\times10^{9}\times5.50\times10^{-6}  }{3.10^{2} }

E = - 5.15 x 10³ V/m

(d) Electric field at 8.00 m is given by the relation as r > R :

E = \frac{KQ}{r^{2} }

Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 8.00 m for r in the above equation.

E = - \frac{9\times10^{9}\times5.50\times10^{-6}  }{8^{2} }

E = - 0.77 x 10³ V/m

8 0
3 years ago
What is folk remedies
mario62 [17]

A "folk" remedy is something you choose to eat, take, or do,
in order to correct some health issue, because your friend,
your grandmother, your religion, your shaman, your astrologer,
or your medicine man says that it's the right thing to do. 

It may or may not be effective, and it may or may not even be
safe.  What distinguishes it from mainstream medicine is that
its practices are based on hearsay, and have not been subjected
to scientific methods of investigation and evaluation.

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3 0
3 years ago
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