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Marina CMI [18]
3 years ago
8

In one sentence, explain how the particles of a substance change as a substance changes from a solid to a liquid to a gas.

Chemistry
1 answer:
mestny [16]3 years ago
5 0

Answer:

An example would be ice.

Explanation:

Because ice starts off as a solid and then when it melts from heat turns into a liquid and then if heated can to into a gas.

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The decomposition of N I 3 to form N 2 and I 2 releases − 290.0 kJ of energy. The reaction can be represented as 2N I 3 (s)→ N 2
ella [17]

Answer:

The change in enthaply when 10.0 g of nitrogen triiodide decomposes is -3.67 kJ.

Explanation:

2NI_3 (s)\rightarrow N_2 (g)+3 I_2 (g), \Delta H_{rxn} =-290.0 kJ

Enthalpy of the reaction when 2 moles of nitrogen triiodide decomposed =\Delta H_{rxn}

\Delta H_{rxn} = -290.0 kJ

Enthalpy of the reaction when 1 moles of nitrogen triiodide decomposed :

\Delta H=\frac{\Delta H_{rxn}}{2}=\frac{-290.0 kJ}{2} =-145.0 kJ

Mass of nitrogen triiodide decomposed = 10.0 g

Moles of nitrogen triiodide = \frac{10.0 g}{395 g/mol}=0.02532 mol

Change in enthaply when 0.02532 moles of nitrogen triiodide decomposed:

\Delta H\times 0.02532=-145 kJ\times 0.02532=-3.67 kJ

3 0
3 years ago
Determine the expression for the equilibrium constant, kc, for the reaction by identifying which terms will be in the numerator
MakcuM [25]

The kc is a representation of how fast the reaction proceeds to their products when it has achieved equilibrium. The activation energy for the forward and the one for the reverse reaction are similar because they attained chemical equilibrium. A chemical equilibrium happens when both of the reactant and products achieve the same concentration. An example is the process of melting and freezing. Melting and freezing for a given substance occurs at the same temperature. Because the temperature at which the solid starts to melt is also the temperature at which the liquid starts to freeze. They are at chemical equilibrium.

3 0
4 years ago
Find the simple interest on a $22,000 principal, deposited for 4 years at a rate of 4.25%
Makovka662 [10]

Answer:

$25,985.25

Explanation:

Assuming it is compounded annually.

5 0
3 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point of 2.60 m K3PO4(aq).
Serga [27]
To find the freezing point, you use the following formula

fp solution= fp solvent - Δfp solution

fp solvent= 0 C (since the solvent was not stated, you can assume is water which freezing point is 0 degree celsius)

but first, we need to find the depression in freezing point (Δfp solution)

Δfp solution= Kf x i x m, where Kf is constant for the solvent, i is the number of particles produced by the solute and m is the molality of the solution.

Kf= 1.86 for water
i= 4 , becausethe solute breaks into 4 ions, K3PO4---> 3K+ + PO4-3
m= 2.60

Δfp solution= (1.86) (4) (2.60)= 19.3 C

fp solution= 0 - 19.3C=<span> -19.3C
</span>

for boiling point, we use a similar formula and way to solve it. 

Δbp solution= bp solvent + Δbp solution

bp solvent= 100 C for water


to find the elevation boiling point (Δbp soln) is equal to:

Δbp solution= Kb x i x m

Kb= 0.512
i= 4
m= 2.60

Δbp solution= (0.512) (4) (2.60)= 5.32 C

bp solution= 100C + 5.32C= <span>105.32 C</span>
6 0
4 years ago
If a machine has an AMA of 1 what does this tell you about the RF and EF?
patriot [66]

Answer:

Although you might think of a machine as complex system of gears, drive belts and and a motor, the definition physicists use is much simpler. A machine is simply a device that does work, and there are only six different types of simple machines. They include the lever, the pulley, the wheel and axle, the screw, the wedge and the inclined plane.

Explanation:

6 0
3 years ago
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