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erica [24]
3 years ago
15

In a disproportionation reaction, the disproportionate substance

Chemistry
2 answers:
trapecia [35]3 years ago
7 0

Answer:

The answer is C: has at least three oxidation states.

Explanation:

you're welcome

Ira Lisetskai [31]3 years ago
7 0

Answer:

C

Explanation:

got it right on Edge

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What law does a balanced chemical equation demonstrate?
DochEvi [55]

Answer:

The law of conservation of mass

Explanation:

A chemical equation is an expression of the net composition change associated with a chemical reaction. It shows how a certain amount of reactants yields a certain amount of products. Both of these amounts are measured in moles. Chemical equations often contain information about the state of the reactants: solid, liquid, gas, or aqueous. In addition, they always adhere to the law of conservation of mass, which holds that matter can change form, but cannot be created or destroyed.

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The Lineweaver–Burk plot, which illustrates the reciprocal of the reaction rate ( 1 / v ) versus the reciprocal of the substrate
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Answer:

  • x-intercept = \frac{-1}{Km}
  • y-intercept = \frac{1}{Vmax}
  • Slope = \frac{Km}{Vm}

Explanation:

Please check the graph attached.

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3 years ago
The alkali metals are those in the leftmost column on the periodic table.
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<span>The answer is Gaseous metals</span>
8 0
4 years ago
A 1.40 L sample of O2 at 645 Torr and 25 °C, and a 0.751 L sample of N2 at 1.13 atm and 25 °C, are both transferred to the same
anyanavicka [17]

Answer:

  • P(O₂) = 0.595 atm
  • P(N₂) = 0.424 atm
  • Total Pressure = 1.019 atm

Explanation:

To solve this problem we use PV=nRT for both gases in their containers, in order to <u>calculate the moles of each one</u>:

  • O₂:

645 Torr ⇒ 645 /760 = 0.85 atm

25°C ⇒ 25 + 273.16 = 298.16 K

0.85 atm * 1.40 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

n = 0.0487 mol O₂

  • N₂:

1.13 atm * 0.751 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

n = 0.0347 mol N₂

Now we can <u>calculate the partial pressure for each gas in the new container</u>, because the number of moles did not change:

  • O₂:

P(O₂) * 2.00 L = 0.0487 mol O₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

P(O₂) = 0.595 atm

  • N₂:

P(N₂) * 2.00 L = 0.0347 mol N₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

P(N₂) = 0.424 atm

Finally we add the partial pressures of all gases to <u>calculate the total pressure</u>:

  • Pt = 0.595 atm+ 0.424 atm = 1.019 atm
6 0
3 years ago
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