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STALIN [3.7K]
2 years ago
9

Why do the particles in a colloid stay suspended in a liquid, while the particles in a suspension settle out?

Chemistry
1 answer:
valentinak56 [21]2 years ago
3 0

Answer:

The particles are spread evenly throughout the dispersion medium, which can be a solid, liquid, or gas. Because the dispersed particles of a colloid are not as large as those of a suspension, they do not settle out upon standing

Explanation:

My teacher asked us this question We had to answer it.

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Compounding Corner on RxNet is the best reference for more information regarding compounding

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3 years ago
X: glucose + oxygen ---- carbon dioxide + water
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Answer:

X

Explanation:

5 0
1 year ago
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For which applications would you choose a liquid over a gas or solid?
DedPeter [7]

Answer:

Washing Clothes & Dissolving Sugar

Explanation:

Think about each application:

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3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas.

4) Carving a sculpture: You would use solid tool and a sold sculpture.

5) Dissolving sugar: You need a liquid to dissolve sugar!

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5 0
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A 0.595 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
zalisa [80]

Answer:

molar mass M(s) = 65.326 g/mol

Explanation:

  • M(s) + H2SO4(aq) → MSO4(aq) + H2(g)

∴ VH2(g) = 231 mL = 0.231 L

∴ P atm = 1.0079 bar

∴ PvH2O(25°C) = 0.03167 bar

Graham´s law:

⇒ PH2(g) = P atm - PvH2O(25°C)

⇒ PH2(g) = 1.0079 bar - 0.03167 bar = 0.97623 bar = 0.9635 atm

∴ nH2(g) = PV/RT

⇒ nH2(g) = ((0.9635 atm)(0.231 L))/((0.082 atmL/Kmol)(298 K))

⇒ nH2(g) = 9.1082 E-3 mol

⇒ n M(s) = ( 9.1082 E-3 mol H2(g) )(mol M(s)/mol H2(g))

⇒ n M(s) = 9.1082 E-3 mol

∴ molar mass M(s) [=] g/mol

⇒ molar mass M(s) =   (0.595 g) / (9.1082 E-3 mol)

⇒ molar mass M(s) = 65.326 g/mol

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