Mass of CO₂ produced : 58.67 g
<h3>Further explanation</h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
CS₂ + 3O₂ -------> CO₂ + 2SO₂
mol of CO₂ based on mol of O₂ as a limiting reactant(CS₂ as an excess reactant)
From the equation, mol ratio of mol CO₂ : mol O₂ = 1 : 3, so mol CO₂ :
mass CO₂ (MW= 44 g/mol) :
Staining specimen with heavy metal salts (e.g. tungsten, molybdenum) allows you to see the specimen better with higher contrast when electron beam deflects off of your sample.
Answer:
El volumen del cuerpo es el mismo al comienzo de la experiencia.
Explicación:
El volumen del cuerpo es el mismo al principio porque el volumen no cambia si la temperatura permanece igual. Si cambiamos la temperatura i. mi. Al aumentar la temperatura, las moléculas comienzan a expandirse y se produce un aumento de volumen mientras que cuando disminuimos la temperatura, las moléculas de esa sustancia comienzan a contraerse y el volumen de esa sustancia disminuye. Entonces concluimos que el volumen depende de la temperatura.
There are 13 atoms in the product
<h3>Further explanation</h3>
Given
Reaction
H2SO4 + 2KOH --> K2SO4 + 2H2O
Required
The number of atoms
Solution
In a chemical equation, there are reactants on the left and products on the right
Reactants : H2SO4 + 2KOH
Products : K2SO4 + 2H2O
The number of atoms is determined by their reaction coefficient and the subscript of the atoms in the compound
K2SO4 (coefficient = 1) :
K = 2 atoms
S = 1 atom
O = 4 atoms
Total atoms = 7 atoms
2H2O(coefficient = 2) :
H = 2 x 2 = 4 atoms
O = 2 x 1 = 2 atoms
Total atoms = 6 atoms
Total = 13 atoms
The correct matches are as follows:
<span>1.instantaneous combustion
</span>G.burning<span>
2.mass of substances before and after a reaction is the same
</span>C.Law of Conservation of Matter<span>
3.substances that combine
</span>A.reactants
<span>
4. Yields or makes
</span>B.arrow symbol
<span>
5.rapid oxidation
</span>F.explosion<span>
6.new substance
</span>D.product
<span>
7.slow oxidation
</span>E.rust
<span>
Hope this answers the question. Have a nice day.
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