9.2 Solve -a2b-a2x-ab2-2abx-ax2-b2x-bx2 = 0
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
Your answer would be -38.9 hope that helped
Answer:
-7 =x
Step-by-step explanation:
−30=5(x+1)
Divide each side by 5
−30/5=5/5 (x+1)
-6 = x+1
Subtract 1 from each side
-6-1 = x+1-1
-7 =x
Total cards = 52
Total red cards = 26
Total black cards = 26
P(one red and one black) = P(red and then black)+ P(black and then red)
P(one red and one black) =(26/52)(26/51) + (26/52)(26/51)
P(one red and one black) = 26/51 (Answer A)
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Answer: 26/51 (Answer A)
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8 litres (amount of 20% solution needed) and 7 litres for (amount of 50% solution needed)
<u>Step-by-step explanation:</u>
Let consider ‘x’ for 20% acid solution and (15 – x) for 50% acid solution. And so, the equation would be as below,
20% in x + 50% in (15 – x) = 15 litres of 34%
Convert percentage values, we get
0.20(x) + 0.50 (15 – x) = 15 (0.34)
0.20 x + 7.5 – 0.50 x = 5.1
-0.3 x + 7.5 = 5.1
0.3 x = 7.5 – 5.1
0.3 x = 2.4

Apply ‘x = 8’ value in (15 – x) we get,
15 – 8 = 7 litres
The value of 7 litres for (amount of 50% solution needed)