The length of a cell phone is 2.2 inches and the width is 4.6 inches. The company
1 answer:
Answer:
The width of the new phone will be of 4.37 inches.
Step-by-step explanation:
This question is solved by proportions, using a rule of three.
In this question:
Length was of 2.2 inches, after the modification is of 2.09 inches.
Width was of 4.6 inches, after the modification is x. So
2.2 - 2.09
4.6 - x
Applying cross multiplication:
The width of the new phone will be of 4.37 inches.
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First, you plot the coordinates to visualize the problem clearly. As you can see in the picture, the longest sides could either be one of those marked in red. This could be initially determined when you use visual estimation. We measure this using the distance formula: d = √[(x2-x1)^2 + (y2-y1)^2)]
Between coordinates (0,3) and (3,6)
d = √[(3-0)^2 + (6-3)^2)]
d= 4.24 units
Between coordinates (2,1) and (5,4)
d = √[(5-2)^2 + (4-1)^2)]
d= 4.24 units
They are of equal length. Both are the longest sides which measures 4.24 units.
Between coordinates (0,3) and (3,6)
d = √[(3-0)^2 + (6-3)^2)]
d= 4.24 units
Between coordinates (2,1) and (5,4)
d = √[(5-2)^2 + (4-1)^2)]
d= 4.24 units
They are of equal length. Both are the longest sides which measures 4.24 units.