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Delicious77 [7]
2 years ago
5

The length of a cell phone is 2.2 inches and the width is 4.6 inches. The company

Mathematics
1 answer:
gayaneshka [121]2 years ago
8 0

Answer:

The width of the new phone will be of 4.37 inches.

Step-by-step explanation:

This question is solved by proportions, using a rule of three.

In this question:

Length was of 2.2 inches, after the modification is of 2.09 inches.

Width was of 4.6 inches, after the modification is x. So

2.2 - 2.09

4.6 - x

Applying cross multiplication:

2.2x = 2.09*4.6

x = \frac{2.09*4.6}{2.2}

x = 4.37

The width of the new phone will be of 4.37 inches.

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Can a math god help me out?
Taya2010 [7]

Answer:

f(1)=70

f(n)=f(n-1)+6

Step-by-step explanation:

One is given the following function:

f(n)=64+6n

One is asked to evaluate the function for (f(1)), substitute (1) in place of (n), and simplify to evaluate:

f(1)=64+6(1)

f(1)=64+6

f(1)=70

A recursive formula is another method used to represent the formula of a sequence such that each term is expressed as a function of the last term in the sequence. In this case, one is asked to find the recursive formula of an arithmetic sequence: that is, a sequence of numbers where the difference between any two consecutive terms is constant. The following general formula is used to represent the recursive formula of an arithmetic sequence:

a_n=a_(_n_-_1_)+d

Where (a_n) is the evaluator term (a_(_n_-_1_)) represents the term before the evaluator term, and (d) represents the common difference (the result attained from subtracting two consecutive terms). In this case (and in the case for most arithmetic sequences), the common difference can be found in the standard formula of the function. It is the coefficient of the variable (n) or the input variable. Substitute this into the recursive formula, then rewrite the recursive formula such that it suits the needs of the given problem,

a_n=a_(_n_-_1_)+d

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2 years ago
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Los 12 rayos hijo el 
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Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

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Vadim26 [7]

Answer:

B

Step-by-step explanation:

<DCE = BCA (vertical angles are congruent)

DC corresponds to CB,

DC/CB = 15/5 = 3

EC corresponds to CA,

EC/CA = 12/4 = 3

Thus, two sides in ∆ABC are proportional to two corresponding sides in ∆EDC, and also, the included angle in ∆ABC and ∆EDC are congruent to each other. Therefore, based on the SAS Similarity Theorem, ∆ABC and ∆EDC are similar.

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