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Nataly_w [17]
3 years ago
8

What is the cell potential of an electrochemical cell that has the half -reactions shown below? Ni^ 2+ +2e Ni A| A|^ 3+ +3e^ -

Chemistry
1 answer:
Nadya [2.5K]3 years ago
3 0
<h3>Answer:</h3>

A. 1.4 V

<h3>Explanation:</h3>

We are given the half reactions;

Ni²⁺(aq) + 2e → Ni(s)

Al(s) → Al³⁺(aq) + 3e

We are required to determine the cell potential of an electrochemical cell with the above half-reactions.

E°cell = E(red) - E(ox)

From the above reaction;

Ni²⁺ underwent reduction(gain of electrons) to form Ni

Al on the other hand underwent oxidation (loss of electrons) to form Al³⁺

The E.m.f of Ni/Ni²⁺ is -0.25 V and that of Al/Al³⁺ is -1.66 V

Therefore;

E°cell = -0.25 V - (-1.66 V)

         = -0.250V + 1.66 V

         = + 1.41 V

         = + 1.4 V

Therefore, the cell potential will be +1.4 V

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kiruha [24]

Answer:

1.2044 × 10^24 oxygen atoms

Explanation:

To convert from moles to atoms, simply multiply the number of moles by Avogadro's number, 6.022 × 10^23

2 × 6.022 × 10^23

=1.2044 × 10^24

4 0
3 years ago
The volume of the granite as
Trava [24]

The volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

<h3>How to calculate volume in cm³?</h3>

The conversion factor of mL and cm³ is given as follows: 1 mL = 1 cm³

According to this question, the volume of the granite as determined by water displacement is 9.35 mL.

This value in cm³ can be converted as follows:

9.35mL × 1 = 9.35cm³

Therefore, the volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

Learn more about volume at: brainly.com/question/1578538

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8 0
2 years ago
if you react 28 grams of butene with excess hydrogen how many grams of butane would you expect to get
liberstina [14]

Answer:

The correct answer is 29 grams.

Explanation:

Based on the given question, the reaction will be,

CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3

The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.

Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.

Therefore, 28 grams of butene when reacts with hydrogen gas to give,

= 58/56 * 28 = 29 grams of butane.

Hence, the mass of butane produced will be 29 grams.

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