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scoray [572]
3 years ago
12

Gather data: Four other pairs of elements in the same chemical family are listed below. List the number of valence electrons in

each element. Beryllium Nitrogen Oxygen Fluorine Magnesium Phosphorus Sulfur Chlorine
Chemistry
2 answers:
Iteru [2.4K]3 years ago
6 0

Explanation:

Valence electrons is the number of electrons in the outermost shell of an atom. For the main group elements, the group number represents the number of valence electrons.

Beryllium

This belongs to the group 2 hence, it has valency of 2.

Nitrogen

This belongs to group 5, hence it has valency of 5.

Oxygen

This belongs to group 6, hence it has valency  of 6.

Fluorine

This belongs to group 7, hence it has valency of 7.

Magnesium

This belongs to group 2, hence it has valency of 2.

Phosphorus

This belongs to group 5, hence it has valency of 5

Sulphur

This belongs to group 6, it has valency of 6

Chlorine

This belongs to group 7, it has valency of 7

Zigmanuir [339]3 years ago
5 0

Answer:

Beryllium: 2 valence electrons.

Nitrogen: 5 valence electrons.

Oxygen: 6 valence electrons.

Fluorine : 7 valence electrons.

Magnesium : 2 valence electrons.

Phosphorus : 5 valence electrons.

Sulphur : 6 valence electrons.

Chlorine : 7 valence electrons.

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2 years ago
Which of these is found in the energy levels of an atom?
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Answer:

Electrons

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3 0
2 years ago
A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture co
DaniilM [7]

Answer:

Explanation:

The air 9% mole% methane have an average molecular weight of:

9%×16,04g/mol + 91%×29g/mol = 27,8g/mol

And a flow of 700000g/h÷27,8g/mol = 25180 mol/h

In the reactor where methane solution and air are mixed:

In = Out

Air balance:

91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)

Where X is the flow rate of air in mol/h = <em>20144 mol air/h</em>

<em></em>

The air in the product gas is

95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = <em>289 kg O₂</em>

43058 mol air×29g/mol <em>1249 kg air</em>

Percent of oxygen is: \frac{289kg}{1249 kg} =<em>0,231 kg O₂/ kg air</em>

<em></em>

I hope it helps!

4 0
2 years ago
Determine the number of moles of iodine that reacts with 50g of aluminum​
frozen [14]

Answer: The correct answer is option B i.e., 2.78 mol

Explanation:

Aluminium reacts with iodine to form Aluminium iodide

$2Al(s)+3I_{2}(s) \to Al_{2}I_{6}(s)$

From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide

We know $No.\,of\,moles=\frac{weight}{molecular\,weight} \\

For 2 moles of Aluminium, $2=\frac{weight}{27}$\\ $weight=2 \times 27=54g$

3 moles of Iodine reacts with 54 g of Aluminium

? moles of iodine react with 50 g of Aluminium

$=\frac{3 \times 50}{54} =2.78 mol$

8 0
3 years ago
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