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Arlecino [84]
3 years ago
9

Two examples of energy transformations are shown. The energy transformations are similar because they both involve transformatio

ns that begin with chemical energy. Begin with electrical energy. Result in radiant energy. Result in mechanical energy.
Chemistry
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

C - result in radiant energy

Explanation:

Gala2k [10]3 years ago
4 0

Answer:

The answers I think you are looking for is Gasoline or Fuel (chemical energy)

Explanation:

Energy transformation involves change or conversion of energy from one form to another. Having two examples of the same form of chemical energy, convert into two or more types of energy, the best example would be gasoline.

GASOLINE/FUEL → CAR BATTERY + LIGHT BULBS (TRAFFICATOR LIGHT)

<em>(chemical)                     (electrical)               (radiant)</em>

GASOLINE/FUEL → INTERNAL COMBUSTION ENGINE

<em>(chemical)                   (mechanical)</em>

You might be interested in
Question 2
Alenkinab [10]

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

8 0
3 years ago
What type of substances make better conductors
baherus [9]
I'm pretty sure its metals that make good conductors.
5 0
3 years ago
Neon is a noble gas because it is stable non reactive and has ____ valence electrons
lesya692 [45]

Answer:

8 .....................

3 0
3 years ago
Reaction of 0.028 g of magnesium with excess hydrochloric acid generated 31.0 mL of hydrogen gas. The gas was collected by water
MA_775_DIABLO [31]

Explanation:

(a)   It is given that magnesium is reacted with hydrochloric acid and the hydrogen evolved is collected at top. This means that hydrochloric acid will be present in a solution (HCl + Water) and the solvent will be water.

Due to evaporation some amount of water will have evaporated and would be present in vapor phase. Therefore, when the reaction occurs only hydrogen will not be present in vapor phase but, will be accompanied by water vapors as well .

Hence, Dalton's law the total pressure of the system will be sum of pressure exerted by hydrogen gas and pressure exerted by water vapors .

Let us assume that the partial pressure of hydrogen gas be "P_H_{2}"

And, the partial pressure of water will be nothing but the vapor pressure of water,

Vapor pressure of water = P_{water}

                                         = 19.8 mm Hg

Total pressure of the system = 746 mm Hg

Total pressure = P_H_{2} + P_{water}

               746 = P_H_{2} + 19.8

or,               P_H_{2} = 746-19.8

                                = 726.2 mm Hg

Hence, partial pressure of hydrogen gas is 726.2 mm Hg.

(b) To calculate volume at STP, we will first calculate at 22^{o}C and 726.2 mm Hg and than convert it to STP conditions.

Therefore, to calculate volume at 22^{o}C and 726.2 mm Hg we will make use of ideal gas law  as follows.

           P = 726.2 mm Hg

             = \frac{726.2}{760}

             = 0.955 atm

          T = 22^{o}C

              = 22+273.15 = 295.15 K

         V = 31 ml = 31 \times 10^{-3} Litre

According to the ideal gas law ,

              PV = nRT

where,      P = pressure of the system ,  

                 V = volume of the gas

                 N = number of moles

                R = 0.0821 liter atm/mole K

                T = Temperature

Hence, putting the given values into the above formula as follows.

   0.955 \times 31 \times 10^{-3} = N \times 0.0821 \times 295.15

                      N = 1.222 \times 10^{-3} moles

Now, the moles of hydrogen won't change. Therefore, let us calculate  volume at STP of 1.222 \times 10^{-3} moles of hydrogen.

Now, at STP T = 273.15 K , P = 1 atm  and N = 1.222 \times 10^{-3} moles

    1 \times V = 1.222 \times 10^{-3} \times 0.0821 \times 273.15 K

       V = 0.027398 Litre

         = 0.027398 \times 1000          (as 1 L = 1000 ml)

         = 27.398 ml

Therefore, volume of hydrogen at STP is 27.398 ml .

(c)  Now, we can write the the reaction for this case as follows.

         Mg + 2HCl \rightarrow MgCl_{2} + H_{2}

As, weight of magnesium = 0.028 grams

      Molar mass of magnesium = 24.3 grams/mole

   Number of moles of magnesium = \frac{mass}{\text{molar mass}}

                                             = \frac{0.028}{24.3}

                                             = 1.15226 \times 10^{-3} moles

Since, it can be seen from the reaction  that

    1 mole of Magnesium = 1 mole of hydrogen

and, moles of hydrogen = 1.15226 \times 10^{-3} moles

                                        = 0.001523 moles

Hence, theoretical number of moles of hydrogen that can be produced from 0.028 grams of Mg is 0.001523 moles

8 0
3 years ago
15A.4(a) What is the temperature of a two-level system of energy separation equivalent to 400 cm−1 when the population of the up
maksim [4K]

Answer:

T = 525K    

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

\frac{N_{i}}{N} = e^{-\Delta E/kT}  (1)

<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>         

The energy between the two levels (ΔE) is:

\Delta E = hck    

<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>      

\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J  

Solving the equation (1) for T:

T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}  

<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>

T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K                                  

I hope it helps you!

3 0
3 years ago
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