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Arlecino [84]
3 years ago
9

Two examples of energy transformations are shown. The energy transformations are similar because they both involve transformatio

ns that begin with chemical energy. Begin with electrical energy. Result in radiant energy. Result in mechanical energy.
Chemistry
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

C - result in radiant energy

Explanation:

Gala2k [10]3 years ago
4 0

Answer:

The answers I think you are looking for is Gasoline or Fuel (chemical energy)

Explanation:

Energy transformation involves change or conversion of energy from one form to another. Having two examples of the same form of chemical energy, convert into two or more types of energy, the best example would be gasoline.

GASOLINE/FUEL → CAR BATTERY + LIGHT BULBS (TRAFFICATOR LIGHT)

<em>(chemical)                     (electrical)               (radiant)</em>

GASOLINE/FUEL → INTERNAL COMBUSTION ENGINE

<em>(chemical)                   (mechanical)</em>

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A breeder nuclear reactor is a reactor in which nonfissile U-238 is converted into fissile Pu-239. The process involves bombardm
VARVARA [1.3K]

<u>Answer:</u> The nuclear equations for the given process is written below.

<u>Explanation:</u>

The chemical equation for the bombardment of neutron to U-238 isotope follows:

_{92}^{238}\textrm{U}+n\rightarrow _{92}^{239}\textrm{U}

Beta decay is defined as the process in which neutrons get converted into an electron and a proton. The released electron is known as the beta particle.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

The chemical equation for the first beta decay process of _{92}^{239}\textrm{U} follows:

_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta

The chemical equation for the second beta decay process of _{93}^{239}\textrm{Np} follows:

_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta

Hence, the nuclear equations for the given process is written above.

6 0
3 years ago
When does boiling occur?
butalik [34]

Water boils at 100 Degrees Celsius or 212 degrees Fahrenheit

8 0
3 years ago
A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?
viva [34]
<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

<h3>   <u> ≈ 4.95 g/L</u></h3>
4 0
3 years ago
Which one(s) below right about valence electrons?
grandymaker [24]
Answer choice A, B, and C is right about the valence electrons. For answer choice D and E, Would in it be a more of an element kind of choice. whether the element is closer to the left side of the periodic table or not determines the high and low energy.
3 0
3 years ago
Read 2 more answers
A quantity of gas occupies a volume of 804 mL at a temperature of 27 °C. At what temperature will the
irga5000 [103]

Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume of gas = 804 mL

Initial temperature = 27°C (27+273=300 K)

Final temperature = ?

Final volume = 402 mL

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁  

T₂ = 402 mL × 300 K / 804 mL

T₂ = 120,600 mL.K / 804 mL

T₂ = 150 K

3 0
3 years ago
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