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riadik2000 [5.3K]
4 years ago
7

How much solute (in mL) would you need to add to solvent in order to create 825 mL of a final solution that is 21% solute by vol

ume? (round to the nearest whole number and do not include units) *
Chemistry
1 answer:
olchik [2.2K]4 years ago
3 0

Answer:21÷100×825 = 173.25

173

Explanation:

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<h2>Solutions:</h2>

<u>Case a:</u> Finding pH for [H⁺] = 1.75 × 10⁻⁵ mol/L :

As we know pH is given as,

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Putting value,

                                  pH  = -log [1.75 x 10⁻⁵]

                                 pH =  4.75

<u>Case b:</u> Finding pH for [H⁺] = 6.50 × 10⁻¹⁰ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [6.50 × 10⁻¹⁰]

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<u>Case c:</u> Finding pH for [H⁺] = 1.0 × 10⁻⁴ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.0 × 10⁻⁴]

                                 pH =  4

<u>Case d:</u> Finding pH for [H⁺] = 1.50 × 10⁻⁵ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.50 × 10⁻⁵]

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3 years ago
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Scilla [17]
-log(10pwer -6) is 6
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3 years ago
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calculate the freezing point of 3.46 gram of a compound X in 160 gram of benzene when a separate sample of X was vaporized it's
Temka [501]

Answer: The freezing point of 3.46 gram of a compound X in 160 gram of benzene is 4.38^0C

Explanation:

The relation of density and molar mass is:

d=\frac{PM}{RT}

where

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P = pressure of the gas  = 773 torr = 1.02 atm   (760 torr = 1atm)

M = molar mass of the gas  = ?

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R = gas constant  = 0.0821Latm/Kmol

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The relation of depression in freezing point with molality:

\Delta T_f=k_f\times m

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5.45-T_f=5.1\times 0.21

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