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riadik2000 [5.3K]
3 years ago
7

How much solute (in mL) would you need to add to solvent in order to create 825 mL of a final solution that is 21% solute by vol

ume? (round to the nearest whole number and do not include units) *
Chemistry
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:21÷100×825 = 173.25

173

Explanation:

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Answer is: 7.8 lb of 21% aluminum and 33.2 ib of <span>42% aluminum.</span>

ω₁<span> = 21% ÷ 100% = 0.21.
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</span>m₁ = ?.

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m₁ = 41 lb - m₂<span>.
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