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valentina_108 [34]
3 years ago
12

A solution of cough syrup contains 5.00% active ingredient by volume. If the total volume of the bottle is 80.0 mL , how many mi

lliliters of active ingredient are in the bottle?
Chemistry
2 answers:
stich3 [128]3 years ago
6 0

Answer:

someone is in my mind and it is telling me 5.55m

Explanation:

QveST [7]3 years ago
5 0

Answer:

4 mL

Explanation:

4mL is 5% of 80mL. Therefore my answer is right.

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What does it mean if an experiment is replicable ? Why is it important that experiment be replicable
Murljashka [212]

Answer:

When an experiment is replicanle it means it is able to be done again.

Explanation:

It is important because You need to see if you get different results or if you messed up the first time

3 0
3 years ago
How do you determine the group and period of an element based on its electron configuration?
il63 [147K]

Answer:

If you are given with the atomic number of an element you can find it's period number and group number. The period number is related to the number of electron occupied shells in the element and the period number is linked to its valence electrons.

Explanation:

hope it helps luv <3

4 0
3 years ago
Solid aluminum and gaseous oxygen react in a combination reaction to produce aluminum oxide: 4Al (s) + 3O2 (g) → 2Al2O3 (s) In
jek_recluse [69]

Answer: The percent yield of the reaction is 74 %

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

\text{Moles of aluminium}=\frac{2.5g}{27g/mol}=0.092mol

For oxygen gas:

\text{Moles of oxygen gas}=\frac{2.5g}{32g/mol}=0.078mol

The chemical equation for the reaction of titanium and chlorine gas follows:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

By Stoichiometry of the reaction:

4 moles of aluminium reacts with 3 moles of oxygen.

So, 0.092 moles of aluminium reacts with = \frac{3}{4}\times 0.092=0.069mol of oxygen

As, given amount of oxygen is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of aluminium produce = 2 moles of Al_2O_3

So, 0.092 moles of aluminium will produce = \frac{2}{4}\times 0.092=0.046moles of Al_2O_3

Now, calculating the mass of aluminium oxide:

\text{Mass of aluminium oxide}=moles\times {\text {molar mas}}=0.046mol\times 102g/mol=4.7g

To calculate the percentage yield of titanium (IV) chloride, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield  = 3.5 g

Theoretical yield = 4.7 g

Putting values in above equation, we get:

\%\text{ yield of reaction}=\frac{3.5g}{4.7g}\times 100\\\\\% \text{yield of reaction}=74\%

Hence, the percent yield of the reaction is 74 %

6 0
3 years ago
What happens when<br> there is a limited<br> resource in an area?
Alecsey [184]

Answer:

it will eventually die off or eventually repopulate

Explanation:

3 0
3 years ago
If nicotine has a molar mass of 160±5g/mol , what is its molecular formula?
navik [9.2K]

Answer:

C10H14N2

Explanation:  

I don't believe one can deduce the molecular formula from just it's molar mass.  There are too many possible combinations of elements that could add to the same mass.  This is the correct formula for nicotine, taken from known information, not from an analysis of the molar mass alone.  One can confirm the molar mass is in the correct range:

C10:  10*12 = 120

H14:   14*1 =    14

N2:     2*14 =  <u> 28</u>

Total =             162  which is 160±5g/mol

8 0
3 years ago
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