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3 years ago

If nicotine has a molar mass of 160±5g/mol , what is its molecular formula?

Chemistry

1 answer:

navik [9.2K]3 years ago

8 0

Answer:

C10H14N2

Explanation:

I don't believe one can deduce the molecular formula from just it's molar mass. There are too many possible combinations of elements that could add to the same mass. This is the correct formula for nicotine, taken from known information, not from an analysis of the molar mass alone. One can confirm the molar mass is in the correct range:

C10: 10*12 = 120

H14: 14*1 = 14

N2: 2*14 = <u> 28</u>

Total = 162 which is 160±5g/mol

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A piece of ebonite and acetate are both rubbed with wool. What will occur when the two pieces (ebonite and acetate) are brought

lesya [120]

Answer: The options are not given, here are the options from another website.

A. They will attract each other

b. They will repel each other

C. Nothing will happen to them

d. They will get heated up

The answer is they will attract each other

Explanation:

This is because the charge from the rubbing of ebonite and acetate to a wool is called triboeletric effect.

When ebonite is rubbed with a wool it will produce negative charge, the electrons around it will be negative but when acetate is rubbed with it, it will produce positive charge. This two will attract each other because unlike charges(negative and positive) attract each other.

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3 years ago

Oxygen is composed of three isotopes: oxygen-16, oxygen-17 and oxygen-18 and has an average atomic mass of 15.9982 amu. Oxygen-1

Irina-Kira [14]

Answer:

The percent abundance of oxygen-18 is 1.9066%.

Explanation:

The average atomic mass of oxygen is given by:

$m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}$

Where:

m: is the atomic mass

%: is the percent abundance

Since the sum of the percent abundance of oxygen isotopes must be equal to 1, we have:

$1 = \%_{16} + \%_{17} + \%_{18}$

$1 = x + 3.2 \cdot 10^{-4} + \%_{18}$

$\%_{18} = 1 - x - 3.2 \cdot 10^{-4}$

Hence, the percent abundance of O-18 is:

$m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}$

$15.9982 = 15.972*x + 16.988*3.2 \cdot 10^{-4} + 17.970*(1 - 3.2 \cdot 10^{-4} - x)$

$x = 0.980614 \times 100 = 98.0614 \%$

Hence, the percent abundance of oxygen-18 is:

$\%_{18} = (1 - 3.2 \cdot 10^{-4} - 0.980614) \times 100 = 1.9066 \%$

Therefore, the percent abundance of oxygen-18 is 1.9066%.

I hope it helps you!

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3 years ago

If two metals both have the same color, have similar densities, and are about the same size, but one is shiny and the other is d

Papessa [141]

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3 years ago

During which phase change does the arrangement of water molecules become more orderly?

KatRina [158]

The phase change in which the water molecules become most orderly is the freezing. This is the process of changing water as liquid to its solidified form. The process of freezing is an exothermic which means that for this to occur, heat should be removed from the system.

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3 years ago

Read 2 more answers

Write the condensed formula from left to right, starting with (CH3)x where x is a number.

pochemuha

Complete question:

Write the condensed formula from left to right, starting with (CH3)x where x is a number.

See attached image for the structure formula of the compound

Answer:

(CH₃)₂CHC(CH₃)₃ named as 2,2,3-Trimethylbutane

Explanation:

If we number the longest chain of the carbon starting from the left, we will observe that there are four carbons in the straight chain as shown in the image.

Starting from first carbon from the left of the carbon chain, at carbon number number 2, there two alkyl group, that is two methyl (CH3 is two). Also at carbon number 3, there are three alkyl group, that is three methyl (CH3 is three).

The condensed formula will be written as;

(CH₃)₂CHC(CH₃)₃

This compound is named as 2,2,3-Trimethylbutane, an isomer of Heptane

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3 years ago