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Mazyrski [523]
3 years ago
15

Graph a line with a y-intercept of 3 and containing the point (2, 5).

Mathematics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

click on the thanks

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I need to know number 5 just what it says thank you
Stels [109]

Answer:

C

Step-by-step explanation:

Okay! Time to use the Pythagoras theorem.

a^2 + b^2 = c^2

4^2 + 7^2 = x^2

16 + 49 = c^2

65 = c^2

Let's take the square root of both sides to get

c ~ 8.06

C

:)

5 0
3 years ago
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Which of the following inequalities is true for ALL real values of x?
attashe74 [19]
(2x)2 > 3x2 is true the first two you can not have two x’s on the same side because where would you put them both when solving them the last one I’m not sure about
4 0
3 years ago
How do I graph the linear equation of y=x+2
Korolek [52]
Replace ‘x’ with what ever number and then add 2, because if you make x a 1 then you would get a three. the equation goes from (x+2)=y to (1+2)=3 so make x whatever you want and then add 2 and you’ll get your ‘y’
6 0
3 years ago
5/2x+1 + 8/2x+1, x≠-1/2
svet-max [94.6K]

\frac{5}{2x + 1} +\frac{8}{2x + 1}

= \frac{5 + 8}{2x + 1}

= \frac{13}{2x + 1}

3 0
3 years ago
The dotted line represents the mid segment of the trapezoid. Find the value of X
Ganezh [65]

<u>Given</u>:

Given that the bases of the trapezoid are 21 and 27.

The midsegment of the trapezoid is 5x - 1.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trapezoid midsegment theorem.

Applying the theorem, we have;

Midsegment = \frac{b_1+b_2}{2}

where b₁ and b₂ are the bases of the trapezoid.

Substituting Midsegment = 5x - 1, b₁ = 21 and b₂ = 27, we get;

5x-1=\frac{21+27}{2}

Multiplying both sides of the equation by 2, we have;

2(5x-1)=(21+27)

Simplifying, we have;

10x-2=48

Adding both sides of the equation by 2, we get;

10x=50

Dividing both sides of the equation by 10, we have;

x=5

Thus, the value of x is 5.

6 0
3 years ago
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