Put it the the the g and 0
Answer:
x > 1/5
Step-by-step explanation:
All of these three triangle inequalities must be satisfied:
AB +BC > AC
BC +CA > BA
CA +AB > CB
___
Taking these one at a time, we have ...
AB +BC > AC
3x +4 + 2x +5 > 4x
x +9 > 0 . . . . . subtract 4x
x > -9
__
BC +CA > BA
2x +5 + 4x > 3x +4
3x > -1 . . . . . . subtract 3x+5
x > -1/3 . . . . . divide by 3
__
CA + AB > CB
4x + 3x +4 > 2x +5
5x > 1 . . . . . . subtract 2x+4
x > 1/5
___
The only values of x that satisfy all of these inequalities are those such that ...
x > 1/5
Hi lol I don’t understand you’re question I need more context
Answer:
The angles formed on line b when cut by the transversal are congruent with ∠2 are 
Step-by-step explanation:
Consider the provided information.
If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .
The angles on the same corners are called corresponding angle.
Alternate Angles: Angles that are in opposite positions relative to a transversal intersecting two lines.
∠2 and ∠6 are corresponding angles
Therefore, ∠2 = ∠6
∠2 and ∠7 are alternate exterior angles
Therefore, ∠2 = ∠7
Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are 
34,600.
7 is higher than 4, so it rounds up.