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Ivenika [448]
3 years ago
9

A triangle has sides represented by 7, x, and x−1. If the perimeter is 28, find the length of the longest side.

Mathematics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

x (11 unit) is the longest side

Step-by-step explanation:

Given:

Sides;

7, x, and x−1

Perimeter = 28

Find:

Longest side

Computation:

Perimeter = sum of all sides

So,

7 + x + (x -1) = 28

2x + 6 = 28

x = 11

So,

x -1 = 11 - 1 = 10 unit

x (11 unit) is the longest side

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Ten times an integer is added to seven times it’s square. If the result is 152, what was the original number?
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Answer:

Required number is 4.

Step-by-step explanation:

Let the required number be a.

Given,

Sum of ten times the integer and seven times it’s square is 152.

= > Ten times of a + seven times of it's square = 152

= > 10( a ) + 7( a )^2 = 152

= > 10a + 7a^2 - 152 = 0

= > 7a^2 + 10a - 152 = 0

= > 7a^2 + ( 38 - 28 )a - 152 = 0

= > 7a^2 + 38a - 28a - 152 = 0

= > a( 7a + 38 ) - 4( 7a + 38 ) = 0

= > ( a - 4 )( 7a + 38 ) = 0

= > a = 4 or - 38 / 7

Hence the required number is 4.

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