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Ivenika [448]
3 years ago
9

A triangle has sides represented by 7, x, and x−1. If the perimeter is 28, find the length of the longest side.

Mathematics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

x (11 unit) is the longest side

Step-by-step explanation:

Given:

Sides;

7, x, and x−1

Perimeter = 28

Find:

Longest side

Computation:

Perimeter = sum of all sides

So,

7 + x + (x -1) = 28

2x + 6 = 28

x = 11

So,

x -1 = 11 - 1 = 10 unit

x (11 unit) is the longest side

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Given triangle ABC with sides AB = 3x + 4 , BC = 2x + 5 , and AC = 4x , determine the values of x such that triangle ABC exists
Jlenok [28]

Answer:

  x > 1/5

Step-by-step explanation:

All of these three triangle inequalities must be satisfied:

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  2x +5 + 4x > 3x +4

  3x > -1 . . . . . . subtract 3x+5

  x > -1/3 . . . . . divide by 3

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3 years ago
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Given that lines a and b are parallel, what angles formed on line b when cut by the transversal are congruent with ∠2?
Kruka [31]

Answer:

The angles formed on line b when cut by the transversal are congruent with ∠2 are \angle{6}\text{ and }\angle{7}

Step-by-step explanation:

Consider the provided information.

If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .

The angles on the same corners are called corresponding angle.

Alternate Angles:  Angles that are in opposite positions relative to a transversal intersecting two lines.

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3 years ago
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