Answer:
A sample of 1068 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?
We need a sample of n.
n is found when M = 0.03.
We have no prior estimate of
, so we use the worst case scenario, which is 
Then






Rounding up
A sample of 1068 is needed.
Increase = 14
Total =50
Percentage increase = 14/50 x 100 = 28%
Answer:
x=28
Step-by-step explanation:
vertical angles are congruent
3x-12=72
3x=84
x=28
<span>We have
</span>

Let's take 6 out from the series

<span>Now multiply and divide by 9
</span>


<span>all 1s add up to n
</span>