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lidiya [134]
3 years ago
12

Diego has learned that the Earth wobbles on its axis in a certain pattern. He predicts that this pattern will repeat every 20,00

0 years. Which of the following ways would be the best way to test Diego's prediction? A. make observations in nature B. make a model C. observe the movement of other planets D. conduct a controlled experiment
Chemistry
2 answers:
nataly862011 [7]3 years ago
8 0
Observe the movment of other planets would be your answer
RSB [31]3 years ago
7 0

Answer:

The answer is B not C

Explanation:

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Define the following terms.
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<em>what</em><em> </em><em>are</em><em> </em><em>the</em><em> </em><em>terms</em><em> </em><em>that</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>be</em><em> </em><em>defined</em><em> </em><em>?</em>

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4 years ago
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The energy associated with motion is
timama [110]
Yes the answer is a , kinetic energy
7 0
3 years ago
2 UO2+ + 4 H+U4+ + UO22+ + 2 H2O is second order in UO2+ and third order overall. Complete the rate law for this reaction in the
mr Goodwill [35]

Answer:

r=k[UO_2^+]^2[H^+]

Explanation:

The given reaction is :-

2UO_2^++4H^+\rightarrow U^{4+}+UO_2^{2+}+2H_2O

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.  

m = 2 =  is order with respect to UO_2^+

n = order with respect to H+

overall order = m+n = 3

n = 3 - m = 3 - 2 = 1

Rate law is:-

r=k[UO_2^+]^2[H^+]

6 0
3 years ago
A sample of a gas in a rigid cylinder with a movable piston has a volume of 11.2 liters at STP. What is the volume of this gas a
posledela

Given that the volume of  cylinder at STP = 11.2 L

Standard temperature = 273 K

Standard pressure = 1 atm

Calculating the volume of gas at 202.6 kPa and 300. K:

Applying the combined gas law,

\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

P_{1} =1 atm

V_{1}=11.2 L

T_{1}=273K  

P_{2}= 202.6 kPa*\frac{1 atm}{101.325 kPa} =2 atm  

V_{2}= ?

T_{2}=300. K  

Plugging in the values and calculating final volume:

\frac{(1atm)(11.2L)}{(273 K)} =\frac{(2atm)(V_{2})}{(300K)}

V_{2}=6.15 L

Therefore the correct answer will be, b) 6.15 L


6 0
3 years ago
Can someone please help me correct A and B please!!!!!!!!
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