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Gnom [1K]
3 years ago
7

A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angl

e 2 is angle 1. The exterior angle at angle 3 is angle 4. The exterior angle at angle 5 is angle 6.
Which is a true statement about the diagram?

m∠5 + m∠6 = m∠1
m∠3 + m∠4 + m∠5 = 180°
m∠1 + m∠2 = 180°
m∠2 + m∠3 = m∠5

i need it to be correct please help<3
Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0
The botem one is correct your welcome
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More help with cylinder math?
meriva
First you will need to find the lateral idea which is
2(15) (3.14) (4)
-multiply them together
Then you will need to find the base.
-3.14x15x4
Then find the surface area
-answer from lateral area and 2(-answer from base-)
Add that and that is ur answer
3 0
3 years ago
Read 2 more answers
C=2m+d solve for m plz
Pavel [41]
Isolate the m, go backwards for PEMDAS.

C = 2m + d
C (-d) = 2m + d (-d)
C - d = 2m
(C - d)/2 = 2m/2
m = (C - d)/2

m = (C - d)/2 is your answer

hope this helps
 
7 0
3 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
1. Integers are not closed under which operation?
velikii [3]

Answer:

Integers are not closed under the DIVISION operation

Example:

(9 ÷ 2 = 4½)

4 0
3 years ago
Help ASAP I don’t get it
GarryVolchara [31]

9514 1404 393

Answer:

  • positive
  • negative

Step-by-step explanation:

The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.

That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.

If k is subtracted, instead of added, then the point will be moved downward.

The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.

_____

<em>Comment on the question</em>

The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.

If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.

3 0
3 years ago
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