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2 years ago

10

have a awesome christmas enjoy the points u will get more I'm going to mark brainliest for the best joke and u will get extra po

ints have a merry christmas

1 answer:

Nikitich [7]2 years ago

5 0

lol im bad at jokes, but hope you have a merry christmas as well !!!

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2 years ago

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The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.

ololo11 [35]

Answer: (a) {a, ar, ar², ar³, ar⁴, ar⁵...}, (b) arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

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3 years ago

When Mr. Key made a chocolate milkshake for himself, he used 3/4 cup

icang [17]

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4/4 is 1 cup.

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3 years ago

Find sin theta if theta is an angle in standard position and the point with coordinates (3, -4) lies on the terminal side of an

alisha [4.7K]

Answer:

$\sin \theta=-\frac{4}{5}$

Step-by-step explanation:

Given:

Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).

So, the 'x' value is 3 and 'y' value id -4.

Using Pythagoras Theorem, we find the hypotenuse.

Hypotenuse = $\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5$

Now, using the sine ratio for the angle, we have

$\sin \theta=\frac{Opposite}{Hypotenuse}\\\sin \theta=\frac{-4}{5}\\\sin \theta=-\frac{4}{5}$

Therefore, the value of $\sin \theta$ is $-\frac{4}{5}$ .

The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,

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3 years ago