If im not wrong which i may not the
Dependent is A
Independent is B
Answer: −3a(−2b−4y).−5x(−2b−4y). to this
6ab+12ay+10bx+20xy
Step-by-step explanation: hope this helps :)
The answer is 1 g
If that is correct
X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)
x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
2x+3y=32_____(2)
(1)×3____9x-6y=27____(3)
(2)×2____4x+6y=64____(4)
(3)+(4)___13x=91
x=7
3(7)-2y=9
-2y=-12
y=6
Answer:
a
Step-by-step explanation:
Given
2| x - 3 | + 5 = 17 ( subtract 5 from both sides )
2| x - 3 | = 12 ( divide both sides by 2 )
| x - 3 | = 6
The absolute value function always returns a positive value but the expression inside can be positive or negative, that is
x - 3 = 6 OR -( x - 3) = 6
x - 3 = 6 ( add 3 to both sides )
x = 9
OR
-( x - 3) = 6 ← distribute left side
- x + 3 = 6 ( subtract 3 from both sides )
- x = 3 ( multiply both sides by - 1 )
x = - 3
As a check
Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
x = 9 → 2|9 - 3| + 5 = 2|6| + 5 = (2 × 6) + 5 = 12 + 5 = 17 ← True
x = - 3 → 2|- 3 - 3| + 5 = 2| - 6 | + 5 = (2 × 6) + 5 = 12 + 5 = 17 ← True
Hence x = 9 or x = - 3 are the solutions → a
