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3 years ago

Question: Is a flame matter? . Claim: (Write a statement that answers the question)

Physics

1 answer:

Alenkinab [10]3 years ago

6 0

Answer:

Matter is anything that has mass and occupies space. The flame itself is a mixture of gases (vaporized fuel, oxygen, carbon dioxide, carbon monoxide, water vapor, and many other things) and so is matter. The light produced by the flame is energy, not matter.

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_________ forces exist between objects that are not in contact with each other.

AveGali [126]

Contact forces is the answer

7 0

2 years ago

An uncharged metal sphere, A, is on an insulating base. A second sphere, B, of the same size, shape, and material carrying charg

solong [7]

Answer:

Explanation:

If we bring the charged sphere B close to, but not touching it , to the uncharged sphere A, as charges can move freely on the conductor, a charge -Q will be built on the outer surface of the sphere A, facing to sphere B.
As the sphere A must remain neutral, a charge Q will be built on the surface, on the side farther to the sphere B, as the following condition must be met:

Q +(-Q) =0.

If we now remove sphere B, and place it far away, there will be a charge redistribution within sphere A, making to disappear the separation between Q and -Q.
The total charge on sphere A must be 0, as there is no charge transfer from sphere B to sphere A.

3 0

3 years ago

Using a horizontal force of 60 N, a wagon is pushed horizontally across the floor a distance of 12 meters at a constant speed of

RideAnS [48]

Answer:

a) The work done by the force is 720 joules, b) The power supplied by the force is 138 watts.

Explanation:

a) Since force is uniform and parallel to the direction of motion, the work ( $W$ ), in joules, done by the force ( $F$ ), in newtons, is defined by this formula:

$W = F\cdot s$ (1)

Where $s$ is the travelled distance, in meters.

If we know that $F = 60\,N$ and $s = 12\,m$ , then the work done by the force is:

$W = F\cdot s$

$W = (60\,N)\cdot (12\,m)$

$W = 720\,J$

The work done by the force is 720 joules.

b) And an expression for the power supplied by the force ( $\dot W$ ), in watts, is concieved by differentiating (1) in time:

$\dot W = F\cdot \dot s$

Where $\dot s$ is the speed of the wagon, in meters per second.

If we know that $F = 60\,N$ and $\dot s = 2.3\,\frac{m}{s}$ , then the power supplied by the force is:

$\dot W = F\cdot \dot s$

$\dot W = (60\,N)\cdot \left(2.3\,\frac{m}{s} \right)$

$\dot W = 138\,W$

The power supplied by the force is 138 watts.

3 0

3 years ago

A race is held between a sports car and a motorcycle. The sports car can accelerate at 5.0 m/s^2 and the motorcycle can accelera

user100 [1]

Answer:

Vf₁ = 30 m/s

s₂ = 90 m

car wins the race.

Explanation:

To find the speed of car after 5 s, we use 1st equation of motion:

Vf₁ = Vi₁ + a₁t₁

where,

Vf₁ = Final Speed of Car = ?

Vi₁ = Initial Speed of Car = 0 m/s

a₁ = acceleration of car = 5 m/s²

t₁ = time = 5 s

Therefore,

Vf₁ = 0 m/s + (5 m/s²)(5 s)

Vf₁ = 25 m/s

To find the distance of motorcycle after 6 s, we use 2nd equation of motion:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₂ = distance covered by the motorcycle = ?

Vi₁ = Initial Speed of motorcycle = 0 m/s

a₂ = acceleration of motorcycle = 8 m/s²

t₂ = time = 6 s

Therefore,

s₂ = (0 m/s)(6 s) + (1/2)(5 m/s²)(6 s)²

s₂ = 90 m

We can use 2nd equation of motion to find time taken by each car and motorcycle to reach the finish point:

For Car:

s₁ = Vi₁ t₁ + (1/2)a₁t₁²

where,

s₁ = 200 m - 50 m = 150 m (since, car starts 50 m ahead)

Therefore.

150 m = (0 m/s)(t₁) + (1/2)(5 m/s²)t₁²

t₁ = √60 s²

t₁ = 7.74 s

For Motorcycle:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₁ = 200 m

Therefore.

200 m = (0 m/s)(t₂) + (1/2)(5 m/s²)t₂²

t₂ = √80 s²

t₂ = 8.94 s

Since, the car takes less time to reach finish line.

Therefore, car wins the race.

5 0

3 years ago

Interactive Solution 9.1 presents a model for solving this problem. The wheel of a car has a radius of 0.300 m. The engine of th

Murrr4er [49]

Answer:

740 N

Explanation:

We are given that

Radius,r=0.3 m

Torque, $\tau=222 Nm$

We have to find the magnitude of the static frictional force.

According to question

Torque by engine=Torque by static friction

$222=f\times r$

$f=\frac{222}{r}$

$f=\frac{222}{0.3}$

$f=740 N$

Hence, the magnitude of static frictional force=740 N

8 0

3 years ago