Answer:
(6) Is proportional to L and inversely proportional to A.
Explanation:
I will explain it mathematically, following formula relates Resistance to length of wire L and cross sectional area A.
here, p is greek letter 'Rho' is called resistivity of the wire and L is lenght and A is cross sectional area of the wire.
By inspection we can tell that as length increases the resistance of wire increase, so resistance must be directly propoetional to length.
and resistance decrease as cross sectional area A decreases.
So the resistance must be directly proportional to Length of wire and inversly proportional to cross sectional area of wire.
option number (6) fits all of our deductions.
To solve this problem we will start by applying the given load ratio, and we will rely on the two types of distances given. Later we will use Gauss's law and through its integrals, in which it is equivalent to the potential we will obtain its value in the center of the sphere. Since it is uniformly charged we have to,
By Gauss Law
Here, E is the electric Field and is equal to
For 
being the Permeability constant at free space
Replacing with the previous value we have,
Then the value of the electric field is,
Now potential
Answer:
True
Explanation:
Modern safer and cheaper nuclear reactors can not only meet the range of our long term energy demands, they can also fight global warming.
Modern techniques provide ways to reduce radioactive waste amount. "A closed fuel cycle may be switched on for new kinds of nuclear plants. Alternatively, the waste is chemically dissuaded to transform the reusable element into fuel. This implies that nuclear waste would not be buried.
Answer:
1.3 g/cm³
Explanation:
The mass of the paint without the tin or lid is:
7 kg − 0.5 kg = 6.5 kg = 6500 g
Density is mass per volume:
d = 6500 g / 5000 cm³
d = 1.3 g/cm³
Speed is the rate at which an object's position changes, measured in meters per second. The equation for speed is simple: distance divided by time. You take the distance traveled (for example 3 meters), and divide it by the time (three seconds) to get the speed (one meter per second).
