It would be, 1.000. Hope that helps :)
Answer:
1.6675×10^-16N
Explanation:
The force of gravity that the space shuttle experiences is expressed as;
g = GM/r²
G is the gravitational constant
M is the mass = 1.0 x 10^5 kg
r is the altitude = 200km = 200,000m
Substitute into the formula
g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²
g = 6.67×10^-6/4×10^10
g = 1.6675×10^{-6-10}
g = 1.6675×10^-16N
Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N
Explanation:
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Answer:
The tension is
The horizontal force provided by hinge
Explanation:
From the question we are told that
The mass of the beam is
The length of the beam is
The hanging mass is
The length of the hannging mass is
The angle the cable makes with the wall is
The free body diagram of this setup is shown on the first uploaded image
The force are the forces experienced by the beam due to the hinges
Looking at the diagram we ca see that the moment of the force about the fixed end of the beam along both the x-axis and the y- axis is zero
So
Now about the x-axis the moment is
=>
Substituting values
Now about the y-axis the moment is
Now the torque on the system is zero because their is no rotation
So the torque above point 0 is
The horizontal force provided by the hinge is
Now substituting for T