Answer:
2.36 μ H
Explanation:
Given,
Number of turns= 90
diameter = 1.3 cm = 0.013 m
unscratched length = 57 cm = 0.57 m
Area, A = π r²
= π x 0.0065² = 1.32 x 10⁻⁴ m²
we know,
L = 2.36 μ H
Hence, the inductance of the unstretched cord is equal to 2.36 μ H
Answer:
e = 1.21 mV
Explanation:
given,
length of rod = 10 m
height of drop = 4.89 m
Earth’s magnetic field = 12.4 µT
acceleration of gravity = 9.8 m/s²
velocity of the beam
v = 9.79 m/s
emf of the beam
e = B l v
e = 12.4 x 10⁻⁶ x 9.79 x 10
e = 1.21 x 10⁻³ V
e = 1.21 mV
Answer:
The magnification would be "103.55". A further explanation is given below.
Explanation:
The given values are:
Distance between lens and eyepiece,
L = 85 cm
Eyepiece is,
= 123 D
Now,
The refractive power of eye piece will be:
⇒
The length of the telescope will be:
⇒
⇒
On substituting the values, we get
⇒
⇒
Now,
The magnification of the telescope will be:
⇒
⇒
⇒