Step-by-step explanation:
after I answered the other one(s), you should be really able to do this yourself.
it is precisely the same method and formula just with different numbers.
what's the problem now ?
y = -16x² + 247x + 141
we assume, the ground is at 0 ft.
so, we need to solve
0 = -16x² + 247 x + 141
the general solution for such quadratic equations is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = -16
b = 247
c = 141
x = (-247 ± sqrt(247² - 4×-16×141))/(2×-16) =
= (-247 ± sqrt(61009 + 9024))/-32 =
= (-247 ± sqrt(70033))/-32
x1 = (-247 + 264.6374879...)/-32 = -0.551171497... s
x2 = (-247 - 264.6374879...)/-32 = 15.9886715... s
again, the negative solution for time did not make any sense, so, x2 is our solution.
the rocket will hit the ground after about 15.99 seconds.
Answer:
the total volume of the cage is 6,048
Step-by-step explanation:
336*18=6,048
hope this helps
Y/4-7=3
y/4=7+3
y/4=10 /4
y=40
C. It’s c bebes hope it get a 100
Solve for
y
y in
2
x
+
y
=
8
2x+y=8.
y
=
8
−
2
x
y=8−2x
2 Substitute
y
=
8
−
2
x
y=8−2x into
4
x
+
6
y
=
24
4x+6y=24.
−
8
x
+
48
=
24
−8x+48=24
3 Solve for
x
x in
−
8
x
+
48
=
24
−8x+48=24.
x
=
3
x=3
4 Substitute
x
=
3
x=3 into
y
=
8
−
2
x
y=8−2x.
y
=
2
y=2
5 Therefore,
x
=
3
y
=
2
x=3
y=2
look in comments to read it better but x=3 y=2 hope this helps :)