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vladimir1956 [14]
3 years ago
9

List the possible rational roots and actual rational roots for the equation x^3-2x^2+x+18=0

Mathematics
2 answers:
serg [7]3 years ago
7 0

Answer: The possible rational roots are  

± 1 , ±2 , ± 4 , ± 5 , ± 10 , ± 20 . The rational roots are   x = − 2 , x = 2 , x = 5 .

Kruka [31]3 years ago
3 0

Answer:

D on Edge

Step-by-step explanation:

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Greatest is the multiplication exponent by algebra times by the quotient

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Find the distance between xequals[Start 2 By 1 Matrix 1st Row 1st Column 8 2nd Row 1st Column negative 5 EndMatrix ]and yequals[
kherson [118]

Answer:

Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85

Step-by-step explanation:

The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.

if Vector X = ( x₁ , x₂)   and  Vector  Y = (y₁ , y₂)

then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²

where, x₁ = 8, x₂ = -5   and  y₁ = -1 , y₂ = -9

Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85

4 0
3 years ago
W÷5=? "With work if needed"
Svetach [21]

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Step-by-step explanation:

8 0
3 years ago
Which number is a solution if the inequality?
Likurg_2 [28]

I am following this post


4 0
4 years ago
Read 2 more answers
​ Quadrilateral ABCD ​ is inscribed in this circle.
Anna [14]
A quadrilateral, has 4 sides and its internal angles sum, add up to 360, now... you have 3 angles give.. .but we don't have C

so.. C is the difference of all the three angles from 360 or  \bf \measuredangle C=360-x-(2x+1)-148\implies \measuredangle C=360-x-2x-1-148   whatever that is, now, you'll get some value in x-terms

so.... now once we know what C is

you can if you want, do a search in google for "inscribed quadrilateral conjecture",  I can do a quick proof if you need one

but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°

so.. what the dickens does all that mean?   well D+B=180 and A+C = 180

now. we know what A is, 2x+1
and by now, you'd know what C is from  360-x-2x-1-148

so... add them together then   and

\bf \begin{array}{cccclllll}
A&+&C&=&180\\
\uparrow &&\uparrow \\
(2x+1)&+&(360-x-2x-1-148)&=&180
\end{array}

solve for "x"


6 0
3 years ago
Read 2 more answers
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