Answer:
At 10:30 A.M.
Step-by-step explanation:
A college offers shuttle service from Dickson Hall or Lot B to its campus quad.
At 9:10 A.M the first shuttle leaves from their locations for the campus.
If the shuttles leave from Lot B every 10 minutes and leave from Dickson Hall every 12 minutes, then both the shuttles will leave their origin at the same time after 60 minutes.
This is because 60 is the smallest multiple of 10 and 12 which is common for them.
Therefore, 10:30 A.M. is the next time when both shuttles will depart for the campus at the same time. (Answer)
To get the unit to equal 1, divide both numbers by the denominator; your answer is the number you get by dividing the numerator by the denominator. Use this method to calculate unit cost, too—you're calculating how much 1 item is worth, after you're given the amount that multiple items cost.
source: google
you have to take 51 plus 11 and add it up. then your answer should be 62 degrees different.
Answer:
A
Step-by-step explanation:
BECAUSE THERE IS ONLI ONE VARIABLE
Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2
This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that
g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2
So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).
Here's proof of both claims
-----------------------------------------
Proof of Claim 1:
f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6
-----------------------------------------
Proof of Claim 2:
h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2
