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schepotkina [342]
2 years ago
12

Please help out its due today :]​

Mathematics
1 answer:
slamgirl [31]2 years ago
6 0

Answer:help this kid

Step-by-step explanation:

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What is the value of x? 3x−8=8x+4/2 Enter your answer in the box
krek1111 [17]

For this case we must find the value of "x" of the following expression:

3x-8 = \frac {8x + 4} {2}

Multiplying by 2 on both sides of the equation:

2 (3x-8) = 8x + 4\\6x-16 = 8x + 4

Subtracting 8x from both sides of the equation:

6x-8x-16 = 4\\-2x-16 = 4

Adding 16 to both sides:

-2x = 4 + 16\\-2x = 20

Dividing between -2 on both sides:

x = \frac {20} {- 2}\\x = -10

Answer:

x = -10

6 0
3 years ago
Read 2 more answers
Find the geometric mean of 2 and 3
Sav [38]
The first step in solving this problem is taking 2 and 3 and multiplying them (2 * 3 = 6) .
Now, for the second step, we will cube it. Since there are 2 numbers, we are going to use the 2nd root (2sqrt(6)) This will give us: 4.89897948557 or 5 if you would round it. This would be the Geometric Mean.
7 0
3 years ago
PLEASE ANSWERRRRRRRRRRR
strojnjashka [21]

Answer:

2/5 or 0.4

Step-by-step explanation:

rise over run is 20/50, simplifies to 2/5

5 0
2 years ago
Special Right Trianglws
Masteriza [31]

Answer:

x = 2\sqrt7

y = 2\sqrt7

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by \sqrt2.

So, let's use leg y, y\sqrt2 = 2\sqrt{14}

Solve for y:

y\sqrt2 = 2\sqrt{14}\\\\y = $\frac{2\sqrt{14}}{\sqrt2}$\\\\y = 2\sqrt7

y = 2\sqrt7, which means that x is also 2\sqrt7

3 0
2 years ago
If z=3−5i, find |z|.
geniusboy [140]

Answer:

Step-by-step explanation:

The absolute value of z is the distance between the point graphed from the complex number and the origin on a complex plane.  In a complex plane, the x axis is replaced by R, real numbers, and the y axis is replaced by i, the complex part of the complex number.  Our real number is positive 3 and the complex number is -5, so we go to the right 3 and then down 5 and make a point.  Connect that point to the origin and then connect the point to the x axis at 3 to construct a right triangle that has a base of 3 and a length of -5.  To find the distance of the point to the origin is to find the length of the hypotenuse of that right triangle using Pythagorean's Theorem.  Therefore:

|z|=\sqrt{(3)^2+(-5)^2} and

|z|=\sqrt{9+25} and

|z|=\sqrt{34}

5 0
3 years ago
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