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2 years ago

Which statement BEST compares the growth of the two functions as x approaches oo?

Mathematics

1 answer:

Karo-lina-s [1.5K]2 years ago

6 0

Answer:

b girl main daal atom answer

Step-by-step explanation:

kas goal feel keep PCL pal PCL

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How do you find the leg of a triangle?

Law Incorporation [45]

If it is right triangle use pythagorean

4 0

3 years ago

Please help I will give you brainiest!!!

rusak2 [61]

9514 1404 393

Answer:

x-intercept: -14/9

y-intercept: 7

Step-by-step explanation:

This is one of the easiest forms for finding intercepts. To find the x-intercept, set y=0 and divide both sides by the coefficient of x.

-9x = 14 . . . . . set y=0

x = -14/9 . . . . divide by -9

To find the y-intercept, set x=0 and divide both sides by the coefficient of y.

2y = 14 . . . . set x=0

y = 7 . . . . . . divide by 2

The x-intercept is -14/9; the y-intercept is 7.

8 0

2 years ago

Find three consecutive odd numbers whose sum is 303

CaHeK987 [17]

$n;\ n+2;\ n+4-three\ consecutive\ odd\ numbers\\\\n+(n+2)+(n+4)=303\\\\3n+6=303\\\\3n=303-6\\\\3n=297\ \ \ \ /:3\\\\n=99\\\\Answer:99;\ 101;\ 103.$

8 0

3 years ago

Read 2 more answers

Does anyone know the answer

alukav5142 [94]

676 out of 650 is 104%

7 0

2 years ago

Prove the divisibility:<br><br>45^45·15^15 by 75^30

garri49 [273]

Answer:

$3^{75}$ .

Step-by-step explanation:

We have been an division problem: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(9*5)^{45}=9^{45}*5^{45}$

$15^{15}=(3*5)^{15}=3^{15}*5^{15}$

$75^{30}=(15*5)^{30}=15^{30}*5^{30}$

Substituting these values in our division problem we will get,

$\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}$

$\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}$

$\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}$

$\frac{3^{105}*5^{60}}{3^{30}*5^{60}}$

$\frac{3^{105}}{3^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{105}}{3^{30}}=3^{105-30}$

$3^{105-30}=3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

7 0

3 years ago