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LuckyWell [14K]
2 years ago
11

How many groups of 6 are in 95?

Mathematics
1 answer:
NikAS [45]2 years ago
8 0

Answer:

15

Step-by-step explanation:

It does not divide evenly, but there are 15 groups of 6 in 95.

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Which is the largest fraction? 3/4, 2/3, 4/6, 8/12
zheka24 [161]

Answer:

3/4

Step-by-step explanation:

First you have to find equivalent fractions.

We can use twelve for this number. 3/4 = 9/12       2/3 = 8/12     4/6=8/12 and of course 8/12=8/12. So we can say that 3/4 is the largest fraction of the bunch.

8 0
3 years ago
Complete the equation and tell what property you used 16+31=31+16
krek1111 [17]
201555555555555555555555555555555

4 0
3 years ago
Does anyone know this answer
Dennis_Churaev [7]
I believe the answer is (x+3)x(x-1) hope this helps
7 0
2 years ago
The mean annual tuition and fees for a sample of 15 private colleges was with a standard deviation of . A dotplot shows that it
Fudgin [204]

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

The mean annual tuition and fees for a sample of 15 private colleges was $35,500 with a standard deviation of $6500. A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from $32,500. State the null and alternate hypotheses. A) H0: 4 = 32,500, H:4=35,500 C) H: 4 = 35,500, H7:35,500 B) H: 4 = 32,500, H : 4 # 32,500 D) H0:41 # 32,500, H : 4 = 32,500

Solution

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 32500

For the alternative hypothesis,

Ha: µ ≠ 32500

This is a two tailed test.

Since the number of samples is small and the population standard deviation is not given, the distribution is a student's t.

Since n = 15,

Degrees of freedom, df = n - 1 = 15 - 1 = 14

t = (x - µ)/(s/√n)

Where

x = sample mean = 35500

µ = population mean = 32500

s = samples standard deviation = 6500

t = (35500 - 32500)/(6500/√15) = 1.79

We would determine the p value using the t test calculator. It becomes

p = 0.095

Assuming alpha = 0.05

Since alpha, 0.05 < than the p value, 0.095, then we would fail to reject the null hypothesis.

7 0
2 years ago
The straight line L has equation y = 2x - 5
Aleksandr-060686 [28]

Answer:

slope of perpendicular line - m = -1/2

passing through (-2,3)

thus,

y-3 = -1/2 (x+2)

or y = -1/2x +2

7 0
2 years ago
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