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aleksley [76]
3 years ago
13

Please I need help I really don’t get this lol

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

The pointer pointing to the grey and white balls are either proton or nuetron i van't really tell cause their grey and white.

The whole clster of balls is the Nucleus

The black balls on the lines are electrons

And the lines are the energy level

Explanation:

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A balloon contains 11.1 g of nitrogen monoxide gas (NO). how many molecules are in the balloon?
grandymaker [24]

The number of molecules that are in balloon are = 2.227 x10^23 molecules

<h3> calculation</h3>

calculate the number of moles of NO

moles = mass/molar mass

molar mass  of NO = 14+ 16 = 30 g/mol

moles is therefore=  11.1 g/30g/mol= 0.37 moles

by use of Avogadro's constant that is

                                     1 mole= 6.02 x10^23  molecules

                                          0.37 =? molecules

=(6.02 x10^23 x  0.37 moles)/ 1mole=2.227 x10^23 molecules

4 0
3 years ago
Polyatomic ion formula for aluminum hydroxide
KonstantinChe [14]

Answer:

Al(OH)3 ? i hope this is what you mean.

7 0
3 years ago
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How many moles of CO2 must dissolve in excess water to produce 12 moles of<br><br> H2CO3?
vodka [1.7K]

Answer:

12 moles of CO₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CO₂ + H₂O —> H₂CO₃

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Finally, we shall determine the number of moles of CO₂ that will dissolve in water to produce 12 moles of H₂CO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Therefore, 12 moles of CO₂ will also dissolve in water to produce 12 moles of H₂CO₃.

Thus, 12 moles of CO₂ is required.

3 0
3 years ago
How is helium which is produced by the conversion of hydrogen into energy related to the solar core
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3 years ago
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larisa [96]

Answer:

Explanation:

equilibrium constant

Kc = [ C ]² / [ A ] [ B ]

= .5² / .2  x 3

= .4167

Let moles of A to be added be n

concentration of A unreacted becomes .2 + n M

increase of product C by .2 M will require use of A  and B be .1 M

So unreacted A = .2 + n - .1 = n + .1

Kc = [ C ]² / [ A ] [ B ]

.4167 = .7² / ( n + .1 ) ( 3 - .1 )

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n = . 3 moles .

So .3 moles of A to be added .

6 0
3 years ago
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