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sweet-ann [11.9K]
3 years ago
15

Una disolución contiene 50 gramos de KOH en 0.25 L de Determine la Molaridad de la disolución

Chemistry
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

1. 3.56 M.

2. 0.99 M.

Explanation:

¡Hola!

1. En este caso, dado que la molaridad de una solution es calculada por medio de la siguiente ecuación:

M=\frac{n}{V}

Es posible calcular la molaridad de 50 gramos de hidróxido de potasio primero calculando las moles en dicha masa por medio de la masa molar:

n=50.0gKOH*\frac{1molKOH}{56.11gKOH}=0.891molKOH

Luego, dado el volumen de la solución, podemos calcular la molaridad:

M=\frac{0.891mol}{0.25L}=3.56M

2. En este segundo ejercicio, procedemos de la misma manera, pues primero calculamos las moles de nitrato de potasio:

n=75gKNO_3\frac{1molKNO_3}{101.1gKNO_3}=0.742mol

Luego, calculamos la molaridad justo como se hizo anteriormente:

M=\frac{0.742mol}{0.35L} \\\\M=0.99M

Best regards!

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3.
sineoko [7]

Answer:

3. V = 0.2673 L

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6. V = 2.224 L

Explanation:

3. assuming ideal gas:

  • PV = RTn

∴ R = 0.082 atm.L/K.mol

∴ V1 = 225 L

∴ T1 = 175 K

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⇒ n = RT/PV

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⇒ V2 = 2.4314 L

5.  V1 = 200 L

∴ P1 = 50 KPa = 0.4935 atm

∴ T1 = 271 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(271 K))/((0.4935 atm)(200 L))

⇒ n = 0.2251 mol

∴ P2 = 100 Kpa = 0.9869 atm

∴ T2 = 14 K

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⇒ V2 = ((0.082 atm.L/K.mol)(273 K)(0.0993 mol))/(0.9997 atm)

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