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3 years ago

Find the slant height, l 24

Mathematics

1 answer:

arsen [322]3 years ago

3 0

Don’t open that file it’s a scam it takes you’re information

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How to use exponents

Ira Lisetskai [31]

5
2 = 32

Exponents are like a simplified or easier version of multiplying
2*2*2*2*2

People use exponents in real life. For an example, they use it for finding cubic feet ,square feet, or area of something or an object.

Sorry if I am bad at explaining this or if I confused you

7 0

4 years ago

1- Which relation is a function?

babymother [125]

Answer:

Step-by-step explanation:

1. bottom left

7 0

3 years ago

Please help me

lisabon 2012 [21]

Answer:

Step-by-step explanation:

3+2x = 4x-7

3+7=4x-2x

x=5

3 0

2 years ago

Read 2 more answers

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

3 0

3 years ago

John is putting a fence around his garden that is shaped like a half circle and a rectangle. A rectangle has a length of 14 feet

charle [14.2K]

Answer:

Area of the garden = 98 + 19.25 = 117.25 ft²

Step-by-step explanation:

Area of the garden = area of the rectangle + area of the semi-circle

Area of the rectangle = L x B = 14 x 7 = 98 ft²

Area of the semi-circle = 1/2 x πR² = 1/2 x 22/7 x 3.5² = 19.25 ft²

Hence area of the garden = 98 + 19.25 = 117.25 ft²

6 0

4 years ago