Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer: £122.4
Step-by-step explanation:
Given
The rate of interest is 4%
The principal invested is £1500
the time period is 2 years
Compound interest is given by

put values
![C.I.=1500(1+0.04)^2-1500\\C.I.=1500[1.04^2-1]\\C.I.=1500[1.0816-1]\\C.I.=1500\times 0.0816\\C.I.=122.4](https://tex.z-dn.net/?f=C.I.%3D1500%281%2B0.04%29%5E2-1500%5C%5CC.I.%3D1500%5B1.04%5E2-1%5D%5C%5CC.I.%3D1500%5B1.0816-1%5D%5C%5CC.I.%3D1500%5Ctimes%200.0816%5C%5CC.I.%3D122.4)
Therefore, interest earned is £122.4
3 to the 1st is 3
3 to the 2nd is 9
3 to the 3rd is 27
3 to the 4th is 81
3 to the 5th is 243
3 to the 6th is 729
Your answer is

because the numbers raised to negative powers must be flipped over the divisor to become positive. Then, when multiplying 2 and z, you add their exponents.