Determine the equation of a parabola that intersects the x-axis at points (-2, 0) and (5, 0).
2 answers:
Answer:
The answer is B
Step-by-step explanation:
1) Since the roots are -2, and 5 we can write this
y=a(x+2)(x-5)
y=a(x²-5x+2x+10)
y=a(x²-3x -10)
2) Examining the options, we can see that all of those options have a=1
Then we can plug into that
y=a(x²-3x -10)
y=x² -3x -10
That's the same as
y=(x+2)(x-5) then its roots are x_1 =-2 , and x_2=5
Answer:
B. y = x² - 3x - 10
Step-by-step explanation:
<em>good luck, i hope this helps :)</em>
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<em>Good luck, you'll need it :)</em>
Answer:
y = 2x + 10
Step-by-step explanation:
Find the slope:
12 - 2 / 1 - (-4)
10 / 5 = 2
Write in point-slope form:
y - 12 = 2(x - 1)
rearrange:
y - 12 = 2x - 2
y = 2x + 10
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