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SpyIntel [72]
3 years ago
8

Factor 16x+40y I don't know how to do this

Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0

Step-by-step explanation:

=16x+40y

=8(2x+5y)

<h3>stay safe healthy and happy.</h3>
Marizza181 [45]3 years ago
4 0

Answer:

8(2x + 5y)

Step-by-step explanation:

You cant fact (take out) 8 from both 16 and 40 since 8 is a factor for both.

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2/6+5/6 as a whole number
Dvinal [7]

Answer:  2/6+5/6 + 1.167

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2 years ago
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David rolls a fair dice 240 times. <br> How many times would David expect to roll a three?
jolli1 [7]

Answer:

40

Step-by-step explanation:

There are 6 numbers on an dice (1-6) Divide 240 by 6 and the reasonable amount of times to roll a 3 is 40 time

4 0
3 years ago
Simplify: -3^2+8÷2×4-|-9|
NNADVOKAT [17]
Follow the order of operations. Evaluate absolute value first.
-3^2+8/2*4-9

Then evaluate exponents
9+8/2*4-9

Then evaluate multiplication and division from left to right
9+4*4-9
9+16-9

Then evaluate addition and subtraction from left to right
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16

Final answer: 16
8 0
3 years ago
It takes jada 20 minutes to walk to school. It takes Andre 80% as long to walk to school.
poizon [28]
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3 0
3 years ago
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According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h
andreyandreev [35.5K]

Answer:

The graph f(x)=x^2-4x+3  has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph f(x)=x^2-4x+3

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation f(x)=x^2-4x+3  the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, f(x)=x^2-4x+3=0

This is a quadratic equation, x^2-4x+3=0

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0

\Rightarrow x(x-1)-3(x-1)=0

\Rightarrow (x-3)(x-1)=0

Using zero product property, a\cdot b=0 \Rightarrow a=0\ or \ b=0

\Rightarrow (x-3)=0 or \Rightarrow (x-1)=0

\Rightarrow x=3 or \Rightarrow x=1

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph f(x)=x^2-4x+3  has two zeros  namely 3 and 1.  

3 0
3 years ago
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