This os the answer. Simply make the top fraction improper the multiply by the reciprical of 6. simplify from there.
No because 2 is positive, positive numbers are always bigger than negative.
(a)
the list would be
-20, -12, -8, -1, 1, 5, 10
the other intergers would have to be greater than 1 in order to be on the correct side and cause 1 to be in the middle. They could be anything but 5 and 10 because these were already chosen.
(b)
the list would be like before
-3 was not included so one of the chosen would be -3 and the other would have to be less than -3 but not -8, -12, or -20 beacuse those were already chosen
Answer:
Answer is C
Step-by-step explanation:
There is one faulty light bulb in each box. 4 boxes 4 bad lightbulbs since there we two in the first to 2+2 is 4
2x+1=5x-44 that would be your equation
next start to simplify
subtract 1 from both sides so you are left with 2x=5x-45
then subtract 5x from both sides and you have -3x=-45
then finally divide -3 from -45 to get x=15
