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Murljashka [212]
4 years ago
5

When sound travels through air, the particles _____. a. vibrate along the direction the wave travels b. vibrate but not in any f

ixed direction c. vibrate perpendicular to the direction wave d. do not vibrate 3
Physics
1 answer:
Mandarinka [93]4 years ago
8 0
Vibrate along the direction the wave travels
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Drinking more water or other fluids
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When thermal energy is added to an object what happens to the motion of the particles
Juli2301 [7.4K]

Answer:

The movement of thermal energy from a substance at a higher temperature to one at a lower temperature is called heat. When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises.

Explanation:

5 0
3 years ago
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In 5 meters, a person running at 0.8 m/s accelerates at 1.6 m/s2. How fast 16 points
frutty [35]

They were going at a velocity 4.07m/s

<u>Explanation:</u>

Distance s =5 m

initial velocity u= 0.8 m/s

Acceleration a =1.6m/s2

We have to calculate the velocity with which they were going afterwards i.e final velocity.

Use the equation of motion

v^2=u^2+2as\\=0.8^2+2\times 1.6\times 5\\=16.64\\v=4.07 m/s

They were going with a velocity 4.07 m/s afterwards.

5 0
3 years ago
What cloud makes hail
MArishka [77]

Answer:

Cumulonimbus

Hail development. Hail is a type of strong precipitation, which is shaped in rainstorms mists (Cumulonimbus). Tempests mists comprises of beads of fluid water (at temperatures lower than 0°с, the beads can be in a thermodynamically instable supercooled condition) and ice gems

Explanation:

3 0
3 years ago
A proton travels at a velocity of 3.0x10^6 m/s in a direction perpendicular to a uniform magnetic field.
Virty [35]

Answer:

0.239 T

Explanation:

Applying,

F = Bvqsin∅................ Equation 1

Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.

make B the subject of the equation

B = F/(vqsin∅)................. Equation 2

From the question,

Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)

Constant: q = 1.602 x 10⁻¹⁹ C

Substitute into equation 2

B =  1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)

B = 1.15×10⁻¹³/(4.806×10⁻¹³)

B = 0.239 T.

Hence the magnetic field = 0.239 T

7 0
3 years ago
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