To solve this problem we will apply the linear motion kinematic equations. From the definition of the final velocity, as the sum between the initial velocity and the product between the acceleration (gravity) by time, we will find the final velocity. From the second law of kinematics, we will find the vertical position traveled.
Here,
v = Final velocity
= Initial velocity
g = Acceleration due to gravity
t = Time
At t = 4s, v = -30m/s (Downward)
Therefore the initial velocity will be
Now the position can be calculated as,
When it has the ground, y=0 and the time is t=4s,
Therefore the cliff was initially to 41.6m from the ground
Answer:
option C
Explanation:
given,
Force on the object = 10 N
distance of push = 5 m
Work done = ?
we know,
work done is equal to Force into displacement.
W = F . s
W = 10 x 5
W = 50 J
Work done by the object when 10 N force is applied is equal to 50 J
Hence, the correct answer is option C
The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
The given parameters:
- <em>Throat area of the nozzle, </em>
<em> = 10 cm² = 0.001 m²</em> - <em>The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²</em>
- <em>Air pressure at sea level = 101.325 kPa</em>
The ratio of the areas of the converging-diverging nozzle is calculated as follows;
From supersonic isentropic table, at 
, we can determine the following;
The tank pressure is calculated as follows;
Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
Learn more about converging-diverging nozzle design here: brainly.com/question/13889483
