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Luba_88 [7]
3 years ago
10

How does knowing the double 6+6=12 help solve the near double 6+7=13?

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Because, if 6 + 6 = 12, then in 6 + 7, 7 can be splitted into 6 + 6 + 1, and so you find it easier...!!

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So 3/4 of 12
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2. The table shows distance, y, that Mario runs in x minutes.
grigory [225]

Answer:

Equation: y = ⅐x

Rate of change: ⅐

Distance = 10 miles

Step-by-step explanation:

Given

The information in the above table

Solving (a): The equation

To get the equation, we need to first calculate the slope (m)

Take any two corresponding values of x and y

(x1,y1) = (7,1)

(x2,y2) = (21,3)

m = (y2 - y1)/(x2 - x1)

m = (3 - 1)/(21 - 7)

m = 2/14

m = ⅐

The equation is calculated using

y - y1 = m(x - x1)

Substitute values for m, x1 and y1

y - 1 = ⅐(x - 7)

y - 1 = ⅐x - 1

Add 1 to both sides

y = ⅐x

Solving (b) Rate of change:

The calculated slope in (a) above represents the rate of change.

So:

Rate of change = Slope = ⅐

Solving (c): Distance when time is 70 minutes

This implies that x = 70

Substitute 70 for x in y = ⅐x

y = ⅐ * 70

y = 10 miles

4 0
3 years ago
A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building. If the top of the ladder sl
algol [13]

Answer:

As per the statement:

A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building.

⇒Length of the ladder against a building = 25 foot

and Length of the bottom of the ladder from the building= 7 feet.

You had Before the slip.

Let x be the height of the building where ladder hits the building

By Pythagoras theorem:

\text{Hypotenuse side}^2=\text{Perpendicular}^2+\text{Base}^2

Here, Perpendicular side = Height of the building = x ,  Base = Length of the bottom of the ladder from the building = 7 foot and Hypotenuse side = 25 foot

Substitute the value to solve for x;

25^2=x^2+7^2

625=x^2+49

or

x^2 = 625-49 = 576

x = \sqrt{576} = 24 foot.

⇒Height of the building = 24 foot

Now, if the ladder slips down 4 feet.

You had after slip

⇒Now, the height of the building becomes = 24-4 = 20 foot.

Let y be the distance from the building wall

then by Pythagoras theorem;

y^2+20^2 = 25^2

y^2+400 =625

y^2 = 625-400 = 225

y=\sqrt{225} = 15 foot.

We have to find how many feet will the bottom slide out.

Since, Originally the distance of the bottom from the building = 7 foot

And now, the distance is = 15 foot.

The bottom slide out will be = 15 - 7 =8 foot

Therefore, 8 feet will the bottom slide out

6 0
3 years ago
If Matrix A is 3 x 4, and Matrix B is 4 x 2, what is the size of matrix BA? If BA is undefined, please state so.
vova2212 [387]

Answer:

Joe Mok

Step-by-step explanation:

Joe MAMA

4 0
3 years ago
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