All categories

3 years ago

Ammonia's unusually high melting point is the result of:__________

Chemistry

1 answer:

krek1111 [17]3 years ago

5 0

Answer:

c. hydrogen bonding.

Explanation:

Hydrogen bonding occurs when hydrogen is covalently bonded to a highly electronegative atom such as oxygen, flourine, nitrogen etc.

Hydrogen bonds are quite strong and are known to lead to elevated boiling points. As a result of hydrogen bonding, ammonia is known to have a high melting and boiling point compared to its relative molecular mass.

You might be interested in

What is the boiling point of water when the external pressure is 187.5 mmhg?

Lostsunrise [7]

i believe the answer is 65°c

8 0

4 years ago

2055 Q. No. 10^-2

insens350 [35]

Answer:

Explanation:

Moles of KOH = $10^{-2}$

Volume of water = 10 liters

Concentration of KOH is given by

$[KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}$

$[KOH]$ is strong base so we have the following relation

$[KOH]=[OH^{-}]=10^{-3}\ \text{M}$

$pOH=-\log [OH^{-}]=-\log10^{-3}$

$\Rightarrow pH=14-3=11$

So, pH of the solution is 11

5 0

3 years ago

DNA has 2 strands. if the sequence of nucleotides of one strand was known, is it possible to use the information to determine th

ANTONII [103]

DNA has four main components.
Adenine=A
Cytosine=C
Guanine=G
Thymine=T

Since each letter has an opposite it would be possible by considering the pairs.
A:T
C:G

So, if one strand went as so:
AGCCTAGGTAC
The corresponding strand would be mirrored with the match: TCGGATCCTG

3 0

3 years ago

How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

Neporo4naja [7]

Answer:

2000 L

General Formulas and Concepts:

Atomic Structure

Moles
Temperature Conversion: K = °C + 273.15

Gas Laws

Ideal Gas Law: PV = nRT

P is pressure
V is volume (in L)
n is number of moles
R is gas constant
T is temperature (in K)

Explanation:

Step 1: Define

[Given] 8.8 moles gas

[Given] 0.12 atm

[Given] 56 °C = 329.15 K

Step 2: Solve for V

Substitute in variables [Ideal Gas Law Formula]: $\displaystyle (0.12 \ atm)V = (8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)$
Isolate V: $\displaystyle V = \frac{(8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)}{(0.12 \ atm)}$
Multiply/Divide [Cancel out units]: $\displaystyle V = 1981.7 \ L$

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs.

1981.7 L ≈ 2000 L

3 0

3 years ago

What is the standard potential, e∘celle∘cell, for this galvanic cell? use the given standard reduction potentials in your calcul

Olin [163]

The standard potential for the given galvanic cell is 0.477 V

<h3>What is electrode potential?</h3>

The electrode potential is the electromotive force of a galvanic cell built using a standard reference electrode and another electrode whose potential is to be found.

There are two types of electrode potential

Oxidation potential - The potential associated with oxidation reaction is known as oxidation potential

Reduction potential - The potential associated with reduction reaction is known as reduction potential

At the anode, oxidation occurs

$Sn(s)\rightarrow Sn^{2+}(aq)+2e^-$

At the cathode, reduction occurs

$Cu^{2+}(aq)+2e^-\rightarrow Cu(s)$

$E^o_{cell} =E^o_{cathode} -E^o_{anode}$

= 0.337 - (-0.140)

= 0.477 V

Thus, The standard potential for the given galvanic cell is 0.477 V

Learn more about electrode potential:

brainly.com/question/17362810

#SPJ4

Disclaimer: The question was given incomplete on the portal. Here is the complete question

Question: What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.

$Sn^{2+}(aq)+2e^-\rightarrow Sn(s)$ , E°red=−0.140 V

$Cu^{2+}(aq)+2e^-\rightarrow Cu(s)$ , E°red=+0.337 V

4 0

2 years ago

Read 2 more answers