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3 years ago

Evaluate: Sin [Tan(0)] Help

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

5 0

Answer:

Sin [Tan(0)]

We know, Tan(0) =0

Therefore, Sin [0] =0

Step-by-step explanation:

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Can someone help me please?!?

Damm [24]

Answer:

k=10

Step-by-step explanation:

g(x)=2x^2+ kx+18

when x=-2

g(-2)=2 (-2)^2 -2k +18

Since when x is -2, y =6

6=2 (-2)^2 -2k +18

6=18+8-2k

2k=26-6

2k=20

k=10

7 0

3 years ago

How do I graph (5, -3), (0, -4)

Lorico [155]

Answer:

5 right and down 3 and (0 means the middle) so middle down 4

Step-by-step explanation:

lit : )

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3 years ago

I need help with this question.

aliina [53]

Answer:

answer below

Step-by-step explanation:

in this case the decimal will be recurring so 1 and 2 thirds is 1.6 recurring and 2 and 7 nigths is 2.7 recurring so just plot in between the intervals so the first one could be between 1.6 and 1.7 and the sexond between 2.7 and 2.8

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4 years ago

I need help! Will mark Brainliest for full answer!!!

Softa [21]

Answer:

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

Explanation:

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

Mathematically, an inverse variation relation is represented as follows:

$y = \frac{k}{x}$

where x and y are the two variables and k is the constant of variation

Now, let's check the givens:

Part a:

We are given that y = 3 and k = 33

Substitute in the original relation and solve for x as follows:

$y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11$

Part b:

We are given that y = 11 and x = 5.2

Substitute in the original relation and solve for k as follows:

$y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2$

Part c:

We are given that x=7.8 and k=72

Substitute in the original relation and solve for y as follows:

$y=\frac{k}{x}=\frac{72}{7.8}=9.2$ to the nearest tenth

Hope this helps :)

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3 years ago

What is the common ratio in this geometric series?

Lerok [7]

For a geometric sequence or geometric series, the common ratio is the ratio of a term to the previous term. This ratio is usually indicated by the variable r. Example: The geometric series 3, 6, 12, 24, 48, . . . has common ratio r = 2.

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3 years ago