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tino4ka555 [31]
4 years ago
13

What is the formula mass of beryllium chloride , becl2?

Chemistry
1 answer:
Semmy [17]4 years ago
7 0
To determine the formula mass of beryllium chloride, BeCl₂, we start up with the basis of one mole first. 

Basis: 1 mole BeCl₂
To determine the molar mass of BeCl₂, we add up the mass of one mole of beryllium and two moles of chlorine. 

    1 mol Be = 9 g/mol 
     1 mol of Cl = 35.45 g/mol

Solving,
    molar mass of BeCl₂ = (1 mol Be)(9 g/mol) + (2 mols Cl)(35.45 g/mol)
             molar mass of BeCl₂ = 79.9 g

Then, we take into consideration that 1 mol is equal to 6.022 x 10²³ formula units. 
            formula mass BeCl₂ = (79.9 g/mol)(1 mol/6.022 x 10²³ formula units)
               formula mass of BeCl₂ = 1.33 x 10⁻²² g/formula unit

<em>Answer: 1.33 x 10⁻²² g/formula unit</em>
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What reaction conditions most effectively conver a cabocxylic acid to a methly ester?
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Answer:

Esterification reaction

Explanation:

When we have to go from an acid to an ester we can use the <u>esterification reaction</u>. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).  

In this case, we need the <u>methyl ester</u>, therefore we have to choose the <u>appropriate alcohol</u>, so we have to use the <u>methanol</u> as reactive if we have to produce the methyl ester.

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During which phase change does the arrangement of water molecules become more orderly?
KatRina [158]
The phase change in which the water molecules become most orderly is the freezing. This is the process of changing water as liquid to its solidified form. The process of freezing is an exothermic which means that for this to occur, heat should be removed from the system. 
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A transformer has 90 turns in the primary coil and 9 turns in the secondary coil If the output voltage is 6 V, what is the input
Afina-wow [57]

Answer:

60 V

Explanation:

From;

Vs/Vp = Ns/Np

Where;

Vs = voltage in the secondary coil = 6V

Vp = voltage in the primary coil= ??

Ns = number of turns in the secondary coil = 9

Np= number of turns in the primary coil = 90

6/Vp = 9/90

Vp= 90 * 6/9

Vp=  60 V

6 0
3 years ago
How many grams of PbBr2 will precipitate when excess CuBr2 solution is added to 77.0 mL of 0.595 M Pb(NO3)2 solution?Pb(NO3)2(aq
Alexxx [7]

Answer:

16.89g of PbBr2

Explanation:

First, let us calculate the number of mole of Pb(NO3)2. This is illustrated below:

Molarity of Pb(NO3)2 = 0.595M

Volume = 77mL = 77/1000 = 0.077L

Mole =?

Molarity = mole/Volume

Mole = Molarity x Volume

Mole of Pb(NO3)2 = 0.595x0.077

Mole of Pb(NO3)2 = 0.046mol

Convert 0.046mol of Pb(NO3)2 to grams as shown below:

Molar Mass of Pb(NO3)2 =

207 + 2[ 14 + (16x3)]

= 207 + 2[14 + 48]

= 207 + 2[62] = 207 +124 = 331g/mol

Mass of Pb(NO3)2 = number of mole x molar Mass = 0.046 x 331 = 15.23g

Molar Mass of PbBr2 = 207 + (2x80) = 207 + 160 = 367g/mol

Equation for the reaction is given below:

Pb(NO3)2 + CuBr2 —> PbBr2 + Cu(NO3)2

From the equation above,

331g of Pb(NO3)2 precipitated 367g of PbBr2

Therefore, 15.23g of Pb(NO3)2 will precipitate = (15.23x367)/331 = 16.89g of PbBr2

8 0
3 years ago
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