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tino4ka555 [31]
4 years ago
13

What is the formula mass of beryllium chloride , becl2?

Chemistry
1 answer:
Semmy [17]4 years ago
7 0
To determine the formula mass of beryllium chloride, BeCl₂, we start up with the basis of one mole first. 

Basis: 1 mole BeCl₂
To determine the molar mass of BeCl₂, we add up the mass of one mole of beryllium and two moles of chlorine. 

    1 mol Be = 9 g/mol 
     1 mol of Cl = 35.45 g/mol

Solving,
    molar mass of BeCl₂ = (1 mol Be)(9 g/mol) + (2 mols Cl)(35.45 g/mol)
             molar mass of BeCl₂ = 79.9 g

Then, we take into consideration that 1 mol is equal to 6.022 x 10²³ formula units. 
            formula mass BeCl₂ = (79.9 g/mol)(1 mol/6.022 x 10²³ formula units)
               formula mass of BeCl₂ = 1.33 x 10⁻²² g/formula unit

<em>Answer: 1.33 x 10⁻²² g/formula unit</em>
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Un globo lleno de helio tenia un volumen de 8.5 L en el suelo a 20°C y a una presión de 750 torr. Cuando se le soltó, el globo s
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Answer:

El volumen del gas era 12.95 L

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Se relaciona la presión y el volumen mediante la ley de Boyle, que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:  P*V=k

Por otro lado, la Ley de Charles consiste en la relación que existe entre el volumen y la temperatura absoluta de una cierta cantidad de gas ideal, el cual se mantiene a una presión constante. Esta ley dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T}=k

Por último, la Ley de Gay Lussac dice que la temperatura absoluta y la presión son directamente proporcionales. Es decir, cuando se mantiene todo lo demás constante, mientras suba la temperatura de un gas subirá también su presión. Y mientras la temperatura del gas baje, lo mismo ocurrirá con la presión:

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\frac{P*V}{T} =k

Cuando se desean estudiar dos diferentes estados, uno inicial y una final de un gas, se puede aplicar:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Recordando que la temperatura debe usarse en grados Kelvin, conoces los siguientes datos:

  • P1: 750 torr
  • V1: 8.5 L
  • T1: 20°C= 293°K (siendo 0°C=273°K)
  • P2: 425 torr
  • V2: ?
  • T2: -20°C= 253 °K

Reemplazando:

\frac{750 torr*8.5 L}{293K} =\frac{425 torr*V2}{253 K}

Resolviendo:

V2=\frac{750 torr*8.5 L}{293K} *\frac{253 K}{425 torr}

V2= 12.95 L

<u><em>El volumen del gas era 12.95 L</em></u>

<u><em></em></u>

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