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Harlamova29_29 [7]
3 years ago
7

This is a specific type of dipole-dipole force that exists between molecules with hydrogen atoms and molecules with nitrogen, ox

ygen or fluorine atoms
Chemistry
2 answers:
RoseWind [281]3 years ago
5 0
Answer:  This description refers to:  "hydrogen bonding" .
______________________________________________________

         
<u>  Hydrogen bonding  </u> is a specific type of "dipole-dipole force" that exists <u /><em><u>between</u> </em> [molecules with hydrogen atoms]  <em><u>and</u> </em> [molecules with nitrogen, oxygen, or fluorine atoms.] .
______________________________________________________
cricket20 [7]3 years ago
5 0

Answer:

This is a specific type of dipole-dipole force is known as H<u><em>ydrogen bonding.</em></u>

Explanation:

Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom attached with an electronegative atom( like : O, N and F) and lone pairs of electrons on an neighboring atoms.

Generally this type of bonding is observed where atoms like nitrogen , oxygen, fluorine attached to another molecule are present in neighbors of a hydrogen atom attached to other molecule. This bonding arises due to the interaction between the  developed partial positive and negative charges on the hydrogen and electronegative atoms.

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Identify the compound with the smallest percent ionic character. identify the compound with the smallest percent ionic character
rosijanka [135]
<span> I'll try. A purely ionic bond, as the name implies is a bond between ions. If that sounds like double-talk it's because some ionic compounds are more ionic than others. A purely covalent compound is one in which the electrons are shared EQUALLY. It turns out that the only compounds in which the electrons are shared equally is one in which both atoms sharing the electrons are of the same element. For example O2, N2, Cl2, I2 or F2. Now suppose you make a compound between Fluorine and Iodine, IF. Since fluorine has a greater attraction for electrons than iodine, the bond will be polar. That is the fluorine part of the molecule will be negative and the iodine part will be positive. The attraction for electrons isn't equal. The same thing happens with ionic bonds. In your first question, the ionic character decreases from NaF through SiF4. Sodium loses an electron quite readily because it achieves a stable neon like configuration. Fluorine attracts an electron very strongly for the same reason. But as you move across the period, two things are happening. First, look at SiF4. Silicon is right in the middle of the period, It can achieve a stable inert gas configuration either by gaining 4 or losing 4 electrons. So it depends upon the electronegativity (the electron grabbing ability) of the atom it's combining with. Since Fluorine has the highest electron grabbing ability of any of the reactive elements, it will tend to pull the electrons away from silicon. But silicon doesn't completely give them up as it would in a purely ionic compound. AlF3 is similar but will tend to give up 3 electrons a little easier than SiF4. MgF2 is even more ionic because it's approaching an inert gas configuration and only need to lose 2 electrons. Can you see what's happening? The closer you get to the middle of a period, the less likely an atom is to give up COMPLETELY its electrons. In question 2 your answer is CO. The elements are close together (which means that their electronic structure is similar) and carbon, like silicon is in the middle of the period so its more likely to share electrons than it is to give them up (form an ionic bond). So it turns out that most chemical bonds are neither completely ionic or covalent but lie in between the two extremes and are called polar covalent. I hope this helps.</span>
4 0
3 years ago
The gain of electrons by an element or ion in a reaction is called __.
dsp73

Answer:

Reduction

Explanation:

took the test

5 0
2 years ago
A compound is found to contain 42.88 % carbon and 57.12 % oxygen by weight. To answer the questions, enter the elements in the o
Ipatiy [6.2K]

Answer:

The empirical formule is CO

Explanation:

Step 1: Data given

Suppose the mass of a compound is 100 grams

Suppose the compound contains:

42.88 % C = 42.88 grams C

57.12 % O = 57.12 grams O

Molar mass C = 12.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = mass C / molar mass C

Moles C = 42.88 grams / 12.01 g/mol

Moles C = 3.57 moles

Moles O = 57.12 grams / 16.0 g/mol

Moles O = 3.57 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 3.57 moles / 3.57 moles = 1

O: 3.57 moles / 3.57 moles = 1

The empirical formule is CO

3 0
3 years ago
What are the coefficients to balance the following equation?<br> ba+br=babr2
scoray [572]
1 ba+2 br——>1 babr2

u just have to make sure u have the same number of each type of atom on either side of the equation:)
8 0
3 years ago
Active transport requires chemical energy. True False
guajiro [1.7K]

Answer:

The answer is true

Explanation:

This process is called passive transport or facilitated diffusion, and does not require energy. The solute can move "uphill," from regions of lower to higher concentration. This process is called active transport, and requires some form of chemical energy.

6 0
3 years ago
Read 2 more answers
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