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Harlamova29_29 [7]
3 years ago
7

This is a specific type of dipole-dipole force that exists between molecules with hydrogen atoms and molecules with nitrogen, ox

ygen or fluorine atoms
Chemistry
2 answers:
RoseWind [281]3 years ago
5 0
Answer:  This description refers to:  "hydrogen bonding" .
______________________________________________________

         
<u>  Hydrogen bonding  </u> is a specific type of "dipole-dipole force" that exists <u /><em><u>between</u> </em> [molecules with hydrogen atoms]  <em><u>and</u> </em> [molecules with nitrogen, oxygen, or fluorine atoms.] .
______________________________________________________
cricket20 [7]3 years ago
5 0

Answer:

This is a specific type of dipole-dipole force is known as H<u><em>ydrogen bonding.</em></u>

Explanation:

Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom attached with an electronegative atom( like : O, N and F) and lone pairs of electrons on an neighboring atoms.

Generally this type of bonding is observed where atoms like nitrogen , oxygen, fluorine attached to another molecule are present in neighbors of a hydrogen atom attached to other molecule. This bonding arises due to the interaction between the  developed partial positive and negative charges on the hydrogen and electronegative atoms.

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Select all the correct answers. Why do real gases not behave exactly like ideal gases? Real gases are always hotter than ideal g
Lemur [1.5K]

Answer:

See below.

Explanation:

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4 0
3 years ago
If one starts with pure NO2(g) at a pressure of 0.500 atm, the total pressure inside the reaction vessel when 2 NO2(g) ⇌ 2 NO(g)
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Answer:

The equilibrium partial pressure of NO2 is 0.152 atm

Explanation:

Step 1: Data given

Initial pressure of NO2 = 0.500 Atm

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Step 2: The balanced equation

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Step 3: The initial pressures

pNO2 = 0.500 atm

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pO2 = 0 atm

Step 4: The pressure at the equilibrium

pNO2 = 0.500 - 2x

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4 0
3 years ago
If ammonia is manufactured at 356 k, is the reaction spontaneous, given that the enthalpy and entropy change for the reaction ar
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G = H - T*S  
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G = -93000 - 356*(-198) = -93000 + 70488 = -22512 j/mol  
As G < 0 then the reaction is spontaneous.
5 0
3 years ago
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