The answer is x=6 and y=4.
6+4=10
and 8 times 6 + 12 times 4 is 96.
Answer:
NO
Step-by-step explanation:
The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:
- N: The number of observations in the population.
- n: The number of observations in the sample.
- The way that the random sample is chosen.
We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is
μ_x=p
σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]
In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:
σ_x = σ / sqrt(n).
Answer:
E ( 1 , -1 ) is in quadrant IV
Answer:
Softball : Speed: 29.68 m/s --- Kinetic Energy: 82.36 Joules
Horse: Speed: 13.33 m/s --- Kinetic Energy: 48,331.40 Joules
Satellite: Speed: 3067.13 m/s --- Kinetic Energy: 3,762,910,000 Joules
I hope this helps! Please give me Brainliest. Sorry for the late response, my power went out.
Given
The first 10 partial sums are as follows:
The rest of the partial sums can be obtained in similar way.
