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Nadusha1986 [10]
3 years ago
7

HELPPPPPPPPP PLSSSSSSSSSSSs

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

603

Step-by-step explanation:

804 divided by 12 is 67 and than multiply the 67 by 9 to get 603

hope this helped :)

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there are red and blue counters in the ratio 3:8. two red counters are taken out and the ratio of red to blue is now 1:3. how ma
OLga [1]
Answer = 48 blue counters

———————————————

There are originally 18 red and 48 blue.

The ratio of 3:8 is multiplied by six

3 x 6 = 18
8 x 6 = 48

Take out two red

18 - 2 = 16

The ratio 16:48 (divide by 3) simplifies to 1:3
so it fits.
3 0
3 years ago
Simplify the expression. -5/8(-3/8-1/4) ​
prisoha [69]

Answer:

25/64

Step-by-step explanation:

To get this answer, first you need to use the distributive property:

(-3/8)(-5/8) - (1/4)(-5/8)

Next, multiply:

15/64 - (-5/32)

Change the negative signs into a positive sign:

15/64 + 5/32

Multiply 5/32 by 2 on both top and bottom:

15/64 + (5)(2)/(32)(2)

You will then get:

15/64 + 10/64

Now, add the numerators. You will get:

25/64

This is your answer. I hope it helped!

5 0
3 years ago
..solve the following as fast as
Artist 52 [7]

Answer:

i hope this will help you

Step-by-step explanation:

a 365+94+35

=494

b 896+423+104

=1423

c 379×25×4

=45480

d 89×125×8

=89000

4 0
3 years ago
HALP!! HALP! kd;afsd;kf;khef;ajsfj;afjafd<br> give a frfr answer tho plzz
mixas84 [53]

Answer:

1. C

2. B

3. $220

4. $100

Step-by-step explanation:

6 0
3 years ago
Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and
Pani-rosa [81]

Given Information:

Population proportion = p =  0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$ \sigma_1 = 0.091 $

$ \sigma_2 = 0.050 $

$ \sigma_3 = 0.016 $

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$ \sigma =  \sqrt{\frac{p(1-p)}{n} } $  

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$ \sigma_1 =  \sqrt{\frac{p(1-p)}{n_1} } $

$ \sigma_1 =  \sqrt{\frac{0.55(1-0.55)}{30} } $

$ \sigma_1 = 0.091 $

For sample size n₂ = 100

$ \sigma_2 =  \sqrt{\frac{p(1-p)}{n_2} } $

$ \sigma_2 =  \sqrt{\frac{0.55(1-0.55)}{100} } $

$ \sigma_2 = 0.050 $

For sample size n₃ = 1000

$ \sigma_3 =  \sqrt{\frac{p(1-p)}{n_3} } $

$ \sigma_3 =  \sqrt{\frac{0.55(1-0.55)}{1000} } $

$ \sigma_3 = 0.016 $

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0
4 years ago
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