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Andrews [41]
3 years ago
11

Please help me with this one

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

Ang AEG= Ang ODL

Option D

Hope it helps

Aleks [24]3 years ago
4 0

Answer:

We need to know that AG is congruent to OL (third option)

Step-by-step explanation:

We need tp know that one of the corresponding angles are congruent and the corresponding sides adjacent to that angle are also congruent to satisfy ASA

We only know the angle and one side, the other side is AG and GL have to be congruent

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Calculate the answer to the correct number of significant digits. (91.01)(10.7)
aalyn [17]

Answer:

974

Step-by-step explanation:

(91.01)*(10.7)

91.01*(10.7)

91.01*10.7

973.80700

974

6 0
3 years ago
3 hours in 11 questions help plsssssss !!!!!!!!!!
e-lub [12.9K]

Answer:

regular a polygon is: c, e, a

irregular is: b

not a polygon is f, d

Step-by-step explanation:

Regular is a normal shape which has angles

Irregular has straight lines all the way.

Not a polygon has not straight lines and sometimes has a gap in between the lines.

Hope this helps.

7 0
2 years ago
PLEASE HELP ME ASAP!!! WILL MAKE YOU BRAINLIEST!!!!
pochemuha

Answer:A

Step-by-step explanation:

Taliban

4 0
3 years ago
Ella already knew 5 appetizer recipes before starting culinary school, and she will learn 2 new
Natalija [7]

A = 2w+5

example: on week three, she would have the recipes from the other weeks that you have to account for as well as the extra five

2(3)+5=11 so A would equal 11 by week three.

Use multiplication because it is essentially repeated addition.

2(from week 1) + 2(from week 2) + 2(from week 3) + 5(prior to school) =11

5 0
3 years ago
In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.
Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

Hence, x value is 12 when y value is 9

3 0
3 years ago
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