She can wear outfits differently in 167 days.
Given that Lucy wants to wear different clothes everyday, and she has 8 dresses, 7 pairs of shoes, and 3 pairs of earrings, and Lucy can choose 1 dress, 1 pair of shoes, and 1 pair of earrings every day, but however 1 dress and 1 pair of shoes don't look good together, to determine, in such circumstances, how many days can she wear outfits differently, the following calculation must be made:
- (8 x 7 x 3) - 1 = X
- 168 - 1 = X
- 167 = X
Therefore, she can wear outfits differently in 167 days.
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Answer:
130 and 211
Step-by-step explanation:
15+17= 32
17+32=49
32+49=81
49+81=130
81+130=211
∑ ( from n = 1 to n =5 ) 3 · ( -2 ) ^( n -1 )
a 1 = 3 · ( -2 ) ^0 = 3
a 2 = 3 · ( - 2 ) = - 6
a 3 = 3 · 4 = 12
a 4 = 3 · ( - 8 ) = - 24
a 5 = 3 · 16 = 48
3 - 6 + 12 - 24 + 48 = 33
Answer: C ) 33
