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3 years ago

Can somebody help me

Mathematics

1 answer:

JulsSmile [24]3 years ago

6 0

Answer:

2nd and obtuse triangle - should be - double check

Step-by-step explanation:

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Write your answer using integers, proper fractions and improper fractions in the simplest form

Elenna [48]

Answer:

y = ⁷/5x + 13/10

Step-by-step explanation:

Recall: equation in slope-intercept form is given as y = mx + b

Thus, let's rewrite 14x - 10y = -13 in this form.

14x - 10y = -13

Add -14x to both sides

-10y = -14x - 13

Divide both sides by -10

-10y/-10 = -14x/-10 - 13/-10

y = ⁷/5x + 13/10

6 0

3 years ago

Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>

Ksju [112]

Step-by-step explanation:

$(\sec A - \csc A)(1 + \cot A + \tan A)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)$

$=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)$

$=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)$

$=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}$

$=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}$

$=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}$

$=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}$

$=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)$

$=\sec^2A\csc A - \csc^2A\sec A$

5 0

3 years ago

3 x 12b = 180 Find the value of b, then add.

Gekata [30.6K]

Anwser:

180/3=60

60/12=5

3x(12x5)=180

b=5

Step-by-step explanation:

5 0

3 years ago

Add using a number line: -9 + (-3) = ___

Tomtit [17]

-12

Mark brainliest please

Hope this helps

3 0

3 years ago

He students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for e

jenyasd209 [6]

.30 increase so it'd be 1.80
they earned 80 dollars more in september
Sep-360
Oct.280

4 0

4 years ago