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Vaselesa [24]
3 years ago
10

(6u^2+5u^2v^2−3uv^2)−(4u^4+5u^2^v^2−5uv)

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0

Answer:

-4u^{4} + 6u^{2} - 5uv - 3uv^{2}

Step-by-step explanation:

Aleksandr [31]3 years ago
4 0

Answer:

-4u^{4}+6u^{2}-5uv-3uv^{2}

Step-by-step explanation:

When subtracting polynomials, first start with distributing the negative sign to the second polynomial:

6u^{2} + 5u^{2} v^{2}-3uv^{2}-4u^{4}-5u^{2}v^{2}+5uv

Simplify by combining like terms:

-4u^{4}+6u^{2}-5uv-3uv^{2}

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vitfil [10]
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(cos x - (sqrt 2)/2)(sec x -1)=0
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=(\cos x-\frac{1}{\sqrt{2}})(\sec x-1)=0 [/tex]

\frac{(\sqrt{2}\cos x-1)}{\sqrt{2}}(\frac{1}{\cos x\ }-1)=0

(Reciprocal Identity)

(\frac{^{\sqrt{2}\\cos  x-1}}{^{\sqrt{2}}})(\frac{1-\cos x}{\cos x})=0

\frac{^{(\sqrt{2}\cos x-1})}{\sqrt{2}}\frac{(1-\cos x)}{\cos x}=0

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\sqrt{2}\cos x-1=0

\sqrt{2}\cos x=1

\cos x=\frac{1}{\sqrt{2}}

x=\frac{\Pi }{4}

and

1-\cos x=0

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x=0

x=0 and x=\frac{\Pi }{4} are the solutions.

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Step-by-step explanation:

4 0
3 years ago
The rate at which a professional tennis player used carbohydrates during a strenuous workout was found to be 1.7 grams per minut
Alex787 [66]

Answer:

<em>m=1.7</em>

<em>C=68 gr</em>

Step-by-step explanation:

<u>Function Modeling</u>

We are given a relationship between the carbohydrates used by a professional tennis player during a strenuous workout and the time in minutes as 1.7 grams per minute. Being C the carbohydrates in grams and t the time in minutes, the model is

C=1.7t

The slope m of the line is the coefficient of the independent variable, thus m=1.7

The graph of C vs t is shown in the image below.

To find how many carbohydrates the athlete would use in t=40 min, we plug in the value into the equation

C=1.7\cdot 40=68\ gr

8 0
3 years ago
Help me solve this with the steps please :/
Dima020 [189]

Answer:

Option (2)

Step-by-step explanation:

By applying tangent rule in the given right triangle,

tan(42°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(42°) = \frac{6}{\text{Width}}

Width = \frac{6}{\text{tan}(42)}

Width = 6.67

Therefore, width of the given triangle is 6.67 units.

Option (2) is the correct option.

3 0
3 years ago
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