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GarryVolchara [31]
4 years ago
13

The graph below shows the solution to which system of inequalities ?

Mathematics
1 answer:
Georgia [21]4 years ago
7 0

Answer:

A

Step-by-step explanation:

A dotted line means its either greater than or less than. A undotted line means its also equal to the number aswell.

To find the right answer all you need is the first part because y has to be greater than or equal to 2 as shown from the graph. So the answer has to be A. As it is the only one that shows this.

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Evaluate 2xy when x=-1/4and y=3
Yanka [14]

Answer:

see above

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3 years ago
Why do people want brainliest sm?
goldenfox [79]

Answer:

Honestly um I started a few days ago yet dont know

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3 years ago
Equation which i dont like math not no brainly my question 3 (k-12)=k-30
vaieri [72.5K]
3 (k-12) = k-30

3k - 36 = k - 30

3k - k = -30 + 36

2k = 6

k = 3
7 0
3 years ago
Read 2 more answers
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
4 years ago
A snail can crawl at a rate of 6 cm in 0.75 minutes. Which representation shows the distance a snail can travel at this rate?
Bogdan [553]

Answer: 0.00133m/s

Step-by-step explanation:

Given

distance crawled by the snail = 6cm = 0.06m

Time taken = 0.75minutes = 0.75*60

Time taken = 45secs

Required

constant rate of change of the snail's crawl (speed)

Speed of the snail = distance/time;

Speed of the snail = 0.06/45

Speed of the snail = 0.00133m/s

Hence the constant rate of change of the snail's crawl in m/s is 0.00133m/s

7 0
2 years ago
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