Antibody mediated immune systems
Antibiotic immune systems
The answer is b. Prop roots.
Mangroves are small trees and shrubs that live in the coastal zone. Mangrove trees must fight rough tides, huge waves, strong winds, and storms. One of adaptation is prop roots. The prop roots grow out the mangrove trunk, branches or other prop roots until they touch the ground. There they develop an underground root system. These roots serve as a support in the conditions characteristic for mangrove.
Answer:
Answer is true.
Explanation:
Generally, it has been discovered , that people with disabilities are deprived of their rights to many national or international benefits. This is because , they do not have the abilities to strive or contend physically with able people. And this has made them to settle for anything that is being given to them.
The process of normalization has really helped to put things back to how it should be, and this has really helped the people with disabilities because, they now have access to facilities or things that able people have access to, even without struggling or contending with them. Because, prefrential treatments has been given to them wherever or whenever they have to share amenities with the able people.
Arteries are generally larger, undergo more blood flow, and exhibit more blood pressure.
Veins are smaller than arteries, and can have valves in certain parts of the body.
Answer:
C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.
Explanation:
The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.
The heterozygous plant Dr/dR will produce 4 types of gametes: two identical to the chromosmes the individual has in its somatic cells (called parental), and two gametes which will be a mix of the alleles in the homologous chromosomes (called recombinant).
- Dr: parental
- dR: parental
- DR: recombinant
- dr: recombinant
To calculate the frequency of each type of gamete, we must use the formula:
Distance (map units) / 100 = frequency of recombination.
18 mu / 100 = 0.18.
The total frequency of recombination between the genes D and R is 0.18, but every time crossing over happens, two recombinant gametes are generated. Therefore, each recombinant gamete will have a frequency of 0.18/2=0.09 = 9%.
The frequency of parental gametes will be:
1 - frequency of recombinant gametes
1 - 0.18 = 0.82
But there are 2 parental gametes, so each of them will have a frequency of 0.82/2=0.41 = 41%.
